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3 years ago

3. What current is drawn by a 90 W light bulb on a 110 V household circuit? Please answer!!!

Physics

1 answer:

Troyanec [42]3 years ago

8 0

Answer:

So to find the current drawn, simply divide the power by the operating voltage. In the United States, most household appliances work at 110 Volts. So the calculation is divide the Wattage by 110.

Explanation:

i don't know if that correct because i just copied and pasted but it sounds right

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NEED HELP!!! ANSWER THESE 4 QUESTIONS FOR 20 POINTS!!!! PLEASE ANSWER!! I WILL GIVE YOU BRAINEST

MatroZZZ [7]

Answer:

1)A

2)C

3)A

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2 years ago

A 1430 kg car speeds up from 7.50 m/s to 11.0 m/s in 9.30 s. Ignoring friction, how much power did that require?(unit=W)PLEASE H

Aleks04 [339]

Answer:

Kinetic energy = (1/2) (mass) (speed²)

Original KE = (1/2) (1430 kg) (7.5 m/s)² = 40,218.75 joules

Final KE = (1/2) (1430 kg) (11.0 m/s)² = 86,515 joules

Work done during the acceleration = (40218.75 - 86515) = 46,296.25 joules

Power = work/time = 46,296.25 joules / 9.3 sec = 4,978.1 watts .

Explanation:

Dont report my answer please

3 0

3 years ago

Brut [27]

Answer:

$\boxed{\sf Work \ done = 4 \ J}$

Given:

Force = 8 N

Distance covered by the body = 50 cm = 0.5 m

Explanation:

Work Done = Force × Distance covered by the body

= 8 × 0.5

= 4 J

6 0

3 years ago

A cook preparing a meal for a group of people is an example of ______

Sati [7]

Answer:

Option B is correct.

Explanation:

Potential energy or chemical potential energy is used to Cook food which is then converted into thermal energy. The type of energy used also depends upon the type of cooking appliances used.

For e.g. stove convert potential energy to thermal energy.

7 0

4 years ago

A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 5.0 km/h

Ratling [72]

Answer

given,

time = 10 s

ship's speed = 5 Km/h

F = m a

a is the acceleration and m is mass.

In the first case

F₁=m x a₁

where a₁ = difference in velocity / time

F₁ is constant acceleration is also a constant.

Δv₁ = 5 x 0.278

Δv₁ = 1.39 m/s

$a_1=\dfrac{1.39}{10}$

a₁ = 0.139 m/s²

F₂ =m x a₂

F₃ = F₂ + F₁

Δv₃ = 19 x 0.278

Δv₃ = 5.282 m/s

a₃=Δv₂ / t

$a_3=\dfrac{5.282}{10}$

a₃ = 0.5282 m²/s

m a₃=m a₁ + m a₂

a₃ = a₂ + a₁

0.5282 = a₂ + 0.139

a₂=0.3892 m²/s

F₂ = m x 0.3892...........(1)

F₁ = m x 0.139...............(2)

F₂/F₁

ratio = $\dfrac{0.3892}{0.139}$

ratio = 2.8

6 0

4 years ago