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3 years ago

How many grams of oxygen (O2), x, are needed to react with the 700 g of iron to produce 1000 g of iron (III) oxide, Fe2O3?

1 answer:

6 0

As we know that, molecular mass of ferric oxide, Fe2O3, is 159.69 grams.
Out of which, iron contributes 111.69 g (2 X 55.845 g) and oxygen contributes
48 g (3 X 16 g).
Each gram of iron (III) oxide contains 111.69/159.69 g of iron and 48/159.69
g of oxygen.
To produce 1000 g iron (III) oxide we need,
Iron = 111.69*1000/159.69 = 699.42 g
Oxygen = 48*1000/159.69 = 300.58 g

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A coin and feather are dropped in a moon. what will fall earlier on ground.give reasons.if they are dropped in the earth,which o

Igoryamba

Answer:

When an object is dropped, the "principal" force that acts on that object is the gravitational force.

Thus, in the absence of air resistance and such, the acceleration of the object will be equal to the gravitational acceleration:

g = 9.8m/s^2

So, when we drop objects in the moon (where there is no air) the acceleration of every object will be exactly the same. (so there is no dependence in the mass or shape of the object)

Thus, if we drop a coin and a feather in the moon, both objects will fall with the same acceleration, and then both objects will hit the ground at the same time.

But if we are in Earth, we can not ignore the air resistance (a force that acts in the opposite direction than the movement of the object)

And this force depends on the shape and mass of the object (for example, something with a really larger surface and really thin, like a sheet of paper will be more affected by this force than a small rock)

Then here, when the air resistance applies, we should expect that the heavier and smaller object (the coin) to be less affected by this force, then the resistance that the coin experiences is smaller, then the coin falls "faster" than the feather.

8 0

3 years ago

You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th

geniusboy [140]

Answer:

Part 1

20 N

Part 2

0.4 m/s²

Part 3

4 m/s

Explanation:

The force which pulls the sled right = 50 N

The friction force exterted towards left by the snow = -30 N

The mass of the sled = 50 kg

Part 1

The sum of the forces on the sled, F = 50 N + (-30) N = 20 N

Part 2

The acceleration of the sled is given as follows;

F = m·a

Where;

m = The mass of the sled

a = The accelertion

a = F/m

∴ a = (20 N)/(50 kg) = 0.4 m/s²

The acceleration of the sled, a = 0.4 m/s²

Part 3

The initial velocity of the sled, u = 2 m/s

The kinematic equation of motion to determine the speed of the sled is v = u + a·t

The speed, <em>v</em>, of the sled after t = 5 seconds is therefore;

v = 2 m/s + 0.4 m/s² × 5 s = 4 m/s.

7 0

3 years ago

Calculate the speed of the object from 5 seconds to 10 seconds. Show your work and don't forget to include the units. (HINT for

Serga [27]

Answer:

Given

mᴀ = mʙ = mᴄ = 62 kg

Fᴀ = 480N

Fʙ = 240 N

Fᴄ = 600 N

Asked

aᴀ, aʙ, aᴄ = ?

Solution

Based on the question, we know that the mass of road A, road B and road C are same. And, the formula of acceleration is

so, we can calculate the acceleration of road A, road B and road C.

• for road A

aᴀ = 7,7419 m/s²

aᴀ = 7,75 m/s²

• for road B

aʙ = 3,8709 m/s²

aʙ = 3,87 m/s²

• for road C

aᴄ = 9,6774 m/s²

aᴄ = 9,68 m/s²

Explanation:

6 0

4 years ago

Molly is jogging on the treadmill. After 20 minutes, her heart rate has not increased, she is able to talk, and she is not sweat

lakkis [162]

Molly could increase her heart rate by turning around and jogging backwards, by jogging on her hands instead of her feet, or by continuing to jog normally but increasing the speed of the treadmill.

3 0

3 years ago

Read 2 more answers

Calculate the equivalent resistance for both circuits.

Allisa [31]

Answer:

Series equivalent resistance: $R_{eq} = 6 \Omega$