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mixer [17]
2 years ago
6

A healthy environment depends on biogeochemical cycles maintaining a balance of input and output. When forests are cut down, whi

ch process of the carbon cycle is most affected? A. Cellular respiration b. Decomposition c. Photosynthesis d. Transpiration
Physics
2 answers:
Ann [662]2 years ago
8 0
The correct answer will be c
romanna [79]2 years ago
3 0

Answer:

c. Photosynthesis

Explanation:

When forests are cut down, photosynthesis does not happen and as a consequence the carbon cycle is not started.

The carbon cycle begins when plants and other autotrophs absorb carbon dioxide from the atmosphere for use in photosynthesis. Photosynthesis and respiration lead the carbon from its inorganic phase to the organic phase and back to the inorganic phase, completing the biogeochemical cycle.

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A standard light bulb emits light rays in _________ directions.
Ainat [17]
Omni-directional. It means all directional.
4 0
2 years ago
A light horizontal spring has a spring constant of 105 N/m. A 2.00 kg block is pressed against one end of the spring, compressin
Savatey [412]

Answer:

The the coefficient of kinetic friction between the horizontal surface and the block is 0.536.

Explanation:

Given that,

Spring constant = 105 N/m

Mass of block = 2.00 kg

Compress = 0.100 m

Distance = 0.250 m

We need to calculate the coefficient of kinetic friction

Using relation between friction force and restoring force

kx=\mu mg

Put the value into the relation

105\times0.1=\mu\times2.00\times9.8

\mu=\dfrac{105\times0.1}{2.00\times9.8}

\mu=0.536

Hence, The the coefficient of kinetic friction between the horizontal surface and the block is 0.536.

8 0
3 years ago
Read 2 more answers
Una pelota de béisbol sale despedida de un bate con una velocidad horizontal de 20 m/s. En un tiempo de 0.25 s, ¿a qué distancia
Tpy6a [65]

Answer:

Translation:

A baseball is thrown from a bat with a horizontal speed of 20 m / s. In a time of 0.25 s, how far will you have traveled horizontally and how much will you have fallen vertically?

Explanation:

This question deals directly with projectile motions and we can use modifications of equation of motion since it's a horizontal motion.

(a). How far will it have travelled;

X = Vo * t

X = 20 * 2.5 = 50m

(b). How much will it have fallen vertically?

y = Voy + ½gt²

But Voy = 0

y = ½ * 9.8 * 2.5²

y = 30.625m

4 0
3 years ago
Two people are holding up the ends of a 4.25-kg wooden plank. A 6.00-kg box sits in the center of the plank. What forces do the
ira [324]

The forces the people exert on the plank is 100.45N

<u>Explanation:</u>

Force of man 1 on plank = F_1

Force of man 2 on plank = F_2

\bold{\text{ \bold{ Acceleration due to gravity}} = 9.8 m/s^2}

Gravitational force on plank = \bold{m\times a = 4.25\times 9.8 = 41.65N}

Gravitational force on box = \bold{m\times a= 6\times 9.8 = 58.8N}

Given hint is forces of people is equal to forces on plank and box

\bold{\Rightarrow F-1 + F_2 = 41.65 + 58.8 = 100.45N}

in the state of equilibrium normal force is equal and opposite to gravitational force.  

5 0
3 years ago
The maximum depth d_max that a diver can snorkel is set by the density of the water and the fact that human lungs can function a
kobusy [5.1K]

Answer:

0.17214 m

Explanation:

P = Pressure difference between inside and outside the chest cavity = 0.05 atm

\rho = Density of fresh water = 1000 kg/m³

\rho_d = Density of water in the Dead Sea= 1500 kg/m³

h = Height

In fresh water

P=\rho gh_1\\\Rightarrow h_1=\dfrac{P}{\rho g}\\\Rightarrow h_1=\dfrac{0.05\times 101325}{1000\times 9.81}\\\Rightarrow h_1=0.51643\ m

In dead sea

P=\rho_d gh_2\\\Rightarrow h_2=\dfrac{P}{\rho_d g}\\\Rightarrow h_2=\dfrac{0.05\times 101325}{1500\times 9.81}\\\Rightarrow h_2=0.34429\ m

The difference in height is 0.51643-0.34429 = 0.17214 m

8 0
3 years ago
Read 2 more answers
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