Question

The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 Right arrow. N2 3I2 The molar mass of NI3 is 394. 71 g/mol. How many moles of I2 will form 3. 58 g of NI3? 0. 00907 moles 0. 00940 moles 0. 0136 moles 0. 0212 moles.

Answer 1

The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.

How we calculate moles?

Moles of any substance will be calculated as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is:

2NI₃ → N₂ + 3I₂

Moles of 3.58g of NI₃ will be calculated as:

n = 3.58g / 394. 71 g/mol = 0.009 moles

From the stoichiometry of the solution, it is clear that:

2 moles of NI₃ = produce 3 moles of I₂

0.009 moles of NI₃ = produce 3/2×0.009=0.0136 moles of I₂

Hence, option (3) is correct i.e. 0.0136 moles.

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