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3 years ago

How are the wavelength and frequency of a wave related?

Chemistry

2 answers:

jasenka [17]3 years ago

5 0

Answer:

frequency increases as wavelength decrease.

Explanation:

frequency = velocity/wavelength

pochemuha3 years ago

4 0

Answer:

Frequncy increases, wavelength decreases

Explanation:

A wave can be defined as the repetitive pattern of a travelling energy. Waves can also be defined as a disturbance from equilibrium (or rest) of a medium which oscillates along a stable region. Examples of waves include: seismic waves, gravitational waves, shock waves, heat waves, sound waves etc

In a standing wave (ie at different points of the wave, amplitude is constant), its properties are:

Amplitude which is the the distance of the disturbance from equilibrium. It can also be defined as the distance between the highest point of the wave(peak or crest) to the lowest point (trough).

Wavelength(lambda) is the distance between one peak to the next peak or one trough to another trough parallel to the direction of propagation.

Frequency, f is the number of times a wave passes a particular point per unit time.

Wave velocity is the speed at which disturbance moves. It can given as an equation:

V = f*(lambda)

It can also be written as:

f = V/(lambda)

From the relationship above,

We can see that an increase in frequency of the wave would lead to a decrease in its wavelength and vice versa.

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Why must power plants spend so much money and be so cautious in dealing with these materials?

shepuryov [24]

If you are referring to nuclear power plants and radioactive materials, then there is a high necessity to be cautious and stay safe because only by being safe you can prevent accidents like those caused in Ukraine and Japan. Unlike other types of power plants whose destruction in case of an accident can relatively easily be contained, nuclear power plants are extremely difficult to manage if things go out of hand since you can destroy the air around it, the water, the food by ruining the soil, and many other things.

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4 years ago

what is the pressure, in atmospheres, of 2.97 mol h2 gas if it has a volume of 73 liters when the temperature is 298 k? 0.50 atm

Triss [41]

P x V = n x R x T

P x 73 = 2.97 x 0.082 x 298

P x 73 = 72.57492

P = 72.57492 / 73

P = 1.0 atm

hope this helps!

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3 years ago

How does air flow when a low-pressure center occurs in the atmosphere?

Monica [59]

Answer:

Explanation:

It is so because the low air pressure create vacuum and the air from high pressure area move toward the low air pressure.

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3 years ago

A weak bond called a ______ bond results from an attraction between a slightly positive region in a molecule and a slightly nega

tamaranim1 [39]

Answer: The weak bond having slightly positive region and a slightly negative region is polar covalent bond.

Explanation:

Covalent bond is defined as the bond which is formed by the sharing of electrons between the atoms. For Example: HCl, $CH_4$ etc..

They are of two types:

Polar covalent bond: This bond is formed when difference in electronegativity between the atoms is present. When atoms of different elements combine, it results in the formation of polar covalent bond.

In this bond, a dipole is created. More electropnegative atom will have a slight negative charge and less electronegative atom will have a slight positive charge. For Example: $CO_2,NO_2$ etc..

Non-polar covalent bond: This bond is formed when there is no difference in electronegativity between the atoms. When atoms of the same element combine, it results in the formation of non-polar covalent bond. For Example: $N_2,O_2$ etc..

Hence, the weak bond having slightly positive region and a slightly negative region is polar covalent bond.

7 0

3 years ago

If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$

$1810.04571428[mL]=V_2$

Adjusting for significant figures, this gives $V_2=1810[mL]$

4 0

2 years ago