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alekssr [168]
2 years ago
10

Describe what the Sim evidence shows you about attraction. Remember to use the words attraction, freedom of movement, kinetic en

ergy, and overcome in your response
Chemistry
1 answer:
Nataly_w [17]2 years ago
3 0

During change of phase, the molecules of a substance acquire enough kinetic energy to overcome the forces of attraction between its molecules.

<h3>What is change of phase?</h3>

Change of phase occurs when a substance acquires enough energy to overcome the forces of attraction between its molecules to transition from one state of matter to another.

During a change of phase, kinetic energy of the molecules of the substance increases due to the application of heat, and the freedom of movement of the molecules increases.

Change of phase can occur as follows;

  • from solid to liquid and vice versa
  • from solid to gas and vice versa
  • from liquid to gas and vice versa

Therefore, during change of phase, the molecules of a substance acquires enough kinetic energy to overcome the forces of attraction between its molecules leading to increased freedom of movement of the molecules.

Learn more about change of phase at: brainly.com/question/502002

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3 years ago
I need help please!!!!!!!!!!!!!!!!!
AleksAgata [21]

Answer:I think its both

Explanation:

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3 years ago
Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
3 years ago
A molecule that forms when atoms of the same element bond together is called a(n)________
Mice21 [21]

Answer: element.


Justification:


1) A molecule is the union of two or more atoms.


2) When two or more atoms of different elements bond together, the molecule formed is a compound.


For example: one atoms of hydrogen and one atom of chlorine form the molecule HCl, which is a compound (hydrogen chloride).


3) When the molecules is formed by two atoms of the same element, it is not called a compound, but element. Some examples of this are the diatomic gases:


H₂: hydrogen


Cl₂: chlorine


Br₂: bromine


O₂: oxygen


S₂: sulfur


N₂: nitrogen.

3 0
3 years ago
Read 2 more answers
Because their particles move and bounce around more freely, gases typically have more _____ than liquids and solids.
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Kinetic energy if it's based on temperature but potential energy is talking in terms of entropy
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