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Annette [7]
3 years ago
8

A certain first-order reaction (A→products) has a rate constant of 7.20×10−3 s−1 at 45 ∘C. How many minutes does it take for the

concentration of the reactant, [A], to drop to 6.25% of the original concentration?
Express your answer with the appropriate units.
Chemistry
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

6,41 min

Explanation:

For the reaction:

A → products

kinetics first-order reaction law is:

ln[A] = ln[A]₀ -kt

Where [A] is concentration of reactant, [A]₀ is initital concentration of reactant, k is rate constant and t is time.

If the concentration of A is 6,25% you can assume:

[A] = 6,25; [A]₀= 100. Replacing:

ln(6,25) = ln(100) -7,20×10⁻³s⁻¹t

-2,7726 = -7,20×10⁻³s⁻¹t

385s = t

In minutes:

385s×\frac{1min}{60s} = <em>6,41 min</em>

<em></em>

I hope it helps!

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A standard galvanic cell is constructed so that the overall cell reaction is as given below where M is an unknown metal. 2 Al3+(
jasenka [17]

Answer:

magnesium metal

Explanation:

According to the redox reaction equation, six electrons were transferred hence n=6 and F= Faraday's constant 96500C. ∆G° is given hence E°cell can easily be calculated as follows:

From ∆G°= -nFE°cell

E°cell= -∆G°/nF= -(-411×10^3/96500×6)

E°cell= 0.7098V

But for Al3+(aq)/Al(s) half cell, E°= -1.66V from standard table of reduction potentials.

E°cell= E°cathode- E°anode but Al3+(aq)/Al(s) half cell is the cathode

Hence

E°anode=E°cathode - E°cell

E°anode= -1.66-0.7098= -2.37V

This is the reduction potential of Mg hence the anode material was magnesium metal

5 0
3 years ago
If 4.9 kg of CO2 are produced during a combustion reaction, how many molecules of CO2 would be produced?
solmaris [256]

Answer:

6.7 x 10²⁶molecules

Explanation:

Given parameters

Mass of CO₂  = 4.9kg  = 4900g

Unknown:

Number of molecules  = ?

Solution:

To find the number of molecules, we need to find the number of moles first.

 Number of moles  = \frac{mass}{molar mass}

          Molar mass of CO₂  = 12 + 2(16)  = 44g/mol

   Number of moles  = \frac{4900}{44}  = 111.36mole

A mole of substance is the quantity of substance that contains the avogadro's number of particles.

       1 mole  = 6.02 x 10²³molecules

     111.36 moles  =   111.36 x 6.02 x 10²³molecules   = 6.7 x 10²⁶molecules

5 0
4 years ago
one mole of sodium chloride is added to 100 ml of water in beaker a. one mole of glucose, c6h12o6, is added to 100 ml of water i
Viefleur [7K]

Twice as much more will the freezing point of water be lowered in beaker a than in beaker b.

<h3>What determines freezing point?</h3>

A liquid's freezing point rises if the intermolecular interactions between its molecules are strong. The freezing point, however, drops if the molecules of inter - molecular are minimal. The process through which a substance transforms from a liquid into a solid is known as freezing.

<h3>How significant is freezing point?</h3>

Freezing points play a big role in occupational safety. A chemical may perhaps turn harmful if held below its freezing point. A critical safety benchmark for assessing the effects of worker exposure to cold environments is the freezing point.

To know more about Freezing point visit:

brainly.com/question/2292439

#SPJ4

5 0
1 year ago
Where does biomass comes from
tino4ka555 [31]
Biomass is an organic material which has stored sunlight in the from of chemical energy<span>  biomass can fuel wood waste, manure, sugarcane, and other byproducts. biomass is a renewable energy source because the energy it comes from is the sun 

i hope this helps </span>
7 0
3 years ago
Help help help. <br> please help me
inysia [295]

Answer:

D

Explanation:

Solar panels are not toxic, so option A goes out the window.

Aesthetics don't really matter, so option B follows it out.

Option C makes a little sense, but less so than Option D. They aren't nearly as heavy as some of our current energy production methods.

Solar panels are expensive,  hard to store properly, and most are between 15 and 20 percent efficiency, compared with a diesel motor's 40 percent.

4 0
3 years ago
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