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Wewaii [24]
3 years ago
6

Four groups of students were each asked to create table listing two elements and two compounds. Only one group’s table was corre

ct. Which group’s table is correct? [Can someone just please answer]

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
5 0
The answer would be group 2
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Chlorine-36 does what
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Answer:

Chlorine-36 undergoes β-decay.

Explanation:

Cl-36 is radioactive. It emits an electron ( a β-particle) to become more stable and forms Ar-36.

The nuclear equation is

_{17}^{36}\text{Cl}\longrightarrow_{-1}^{0}\text{e} + _{18}^{36}\text{Ar}

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4 years ago
A possible mechanism for the overall reaction represented above is the following.
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A

Explanation:

The slow step of the reaction is the rate determining step. This means to get the rate law for a chemical activity with slow and fast steps, we have to consider the slow step if we are to write the rate law successfully.

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Cat added a sample of sodium hydroxide to water and
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Answer: 2

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Explanation about the combining powers of element chemistry
stiv31 [10]

Answer:

<em>Valency is the combining power of an element. Elements in the same group of the periodic table have the same valency. The valency of an element is related to how many electrons are in the outer shell. The noble gases have the valency 0 as they do not usually combine with other elements.</em>

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3 years ago
A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the
butalik [34]

Answer:

0.172 M

Explanation:

The reaction for the first titration is:

  • HCl + NaOH → NaCl + H₂O

First we <u>calculate how many HCl moles reacted</u>, using the <em>given concentration and volume</em>:

  • 19.6 mL * 0.189 M = 3.704 mmol HCl

As one HCl mol reacts with one NaOH mol, <em>there are 3.704 NaOH mmoles in 25.0 mL of solution</em>. With that in mind we <u>determine the NaOH solution concentration</u>:

  • 3.704 mmol / 25.0 mL = 0.148 M

As for the second titration:

  • H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

We <u>determine how many NaOH moles reacted</u>:

  • 34.9 mL * 0.148 M = 5.165 mmol NaOH

Then we <u>convert NaOH moles into H₃PO₄ moles</u>, using the <em>stoichiometric coefficients</em>:

  • 5.165 mmol NaOH * \frac{1mmolH_3PO_4}{3mmolNaOH} = 1.722 mmol H₃PO₄

Finally we <u>determine the H₃PO₄ solution concentration</u>:

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5 0
3 years ago
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