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2 years ago

3.

Mathematics

1 answer:

Semmy [17]2 years ago

8 0

Answer:

20m+60

Step-by-step explanation:

given,

mark=m

june=m+6(6 years older that mark)

so,

after 10 years,

10(m+(m+6)

=10(2m+6)

=20m+60

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Use synthetic division to evaluate f(x) = –2x^3+ 3x – 6 when x = -5.

fgiga [73]

Answer:

-131

Step-by-step explanation:

Use -5 in place of x

f(x) = –2x^3+ 3x – 6

f(x) = -2*-5^3+3*5-6

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2 years ago

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Answer:

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3 years ago

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Write each fraction or mixed number as a decimal. 3 1/5=?

kompoz [17]

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3 years ago

Maggie earns money from working at the pet store and answering phones. She earns $10 each hour she works at the pet store and $0

kvv77 [185]

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3 years ago

Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s

vivado [14]

Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so the critical value is z = 2.575.

The estimate and the sample size are given by:

$\pi = 0.36, n = 100$ .

Then the bounds of the interval are:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.2364$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.4836$

The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago