Answer:
A. The reactants are= Li and O2
The balanced equation is:
4Li + O2 —> 2Li2O
B. The products are: MgCl2 and O2
The balanced equation is:
Mg(ClO3)2 —> MgCl2 + 3O2
C. The products are: Ca(NO3)2 and H2O
The balanced equation is:
2HNO3 + Ca(OH)2 —> Ca(NO3)2 +
2H2O
D. The products are: CO2 and H2O
The balanced equation is:
C5H12 + 8O2 —> 5CO2 + 6H2O
Explanation:
A. ____ —> Li2O
The reactants are Li and O2. Thus the equation is given below:
Li + O2 —> Li2O
Thus the equation is balanced as follow:
There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by putting 2 in front of Li2O as shown below:
Li + O2 —> 2Li2O
Now, we have 4 atoms of Li on the right side and 1 atom on the left. It can be balance by putting 4 in front of Li as shown below:
4Li + O2 —> 2Li2O
Now the equation is balanced
B. Mg(ClO3)2 —> __
The products are MgCl2 and O2
The equation is given below:
Mg(ClO3)2 —> MgCl2 + O2
The equation can be balance as follow:
There are 6 atoms of O on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:
Mg(ClO3)2 —> MgCl2 + 3O2
Now the equation is balanced
C. HNO3 + Ca(OH)2 —>___
The products are: Ca(NO3)2 and H2O
The equation is given below:
HNO3 + Ca(OH)2 —> Ca(NO3)2 + H2O
The equation is balanced as follow:
There are 2 atoms of NO3 on the right side and 1 atom on the left. It can be balance by putting 2 in front of HNO3 as shown below:
2HNO3 + Ca(OH)2 —> Ca(NO3)2 + H2O
There are a total of 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:
2HNO3 + Ca(OH)2 —> Ca(NO3)2 + 2H2O
Now the equation is balanced
D. C5H12 + O2 —>__
The products are: CO2 and H2O
The equation is given below:
C5H12 + O2 —> CO2 + H2O
The equation can be balance as follow:
There are 5 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 5 in front of CO2 as shown below:
C5H12 + O2 —> 5CO2 + H2O
There are 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:
C5H12 + O2 —> 5CO2 + 6H2O
Now, there are a total of 16 atoms of O on the right side and 2 atoms on the left. It can be balance by putting 8 in front of O2 as shown below:
C5H12 + 8O2 —> 5CO2 + 6H2O
Now we can see that the equation is balanced.
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