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AlekseyPX
4 years ago
7

Which atom attracts electrons more strongly?

Chemistry
2 answers:
lesya [120]4 years ago
3 0
Bromine attracts electrons more strongly. Cesium is In fact the least electro negative element.

Sodium is more likely to lose an electron because is is less electro negative. Strong electronegativity make the element want more electrons. Sodium has loose electrons with a lower electronegativity so it gives it up easier.
makvit [3.9K]4 years ago
3 0

Explanation:

1.    Cesium (Cs) is a group 1 element and it has electronic configuration [Xe] 6s^{1}.

On the other hand, bromine is a group 7 element and it has electronic configuration [Ar] 3d^{10}4s^{2}40^{5}.

Since, Cs is a metal so it will readily lose 1 electron but bromine being a non-metal needs 1 electron to completely fill its orbital.

Hence, bromine atom will attract electrons more strongly.

2.   Sodium (Na) is a a group 1 element and it has electronic configuration 1s^{2}2s^{2}2p^{6}3s^{1}.

Whereas, chlorine is a group 7 element and it has electronic configuration 1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}.

So, sodium is a metal hence, it readily loses its one electron and chlorine being a non-metal will attract one electron in order to completely fill its orbital.

Thus, we can conclude that sodium (Na) atom loses an electron more readily.

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How many moles of Ag+ ions are present in 10 ml of a 0.75 M AgNO3 solution?
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Answer:

b. 7.5 x 10^-3

Explanation:

To solve this problem we need to keep in mind the <em>definition of molarity</em>:

  • Molarity = moles of solute / liters of solution

With the above information in mind it is possible to calculate the moles of solute, given the volume (10 mL) and concentration (0.75 M) of the solution:

  • First we<u> convert 10 mL to L</u> ⇒ 10 mL / 1000 = 0.01 L

Then we <u>calculate the moles of AgNO₃</u>:

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<em>One mole of AgNO₃ contains one mole of Ag⁺</em>, thus the number of Ag⁺ moles is also 7.5x10⁻³.

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