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AlekseyPX
3 years ago
7

Which atom attracts electrons more strongly?

Chemistry
2 answers:
lesya [120]3 years ago
3 0
Bromine attracts electrons more strongly. Cesium is In fact the least electro negative element.

Sodium is more likely to lose an electron because is is less electro negative. Strong electronegativity make the element want more electrons. Sodium has loose electrons with a lower electronegativity so it gives it up easier.
makvit [3.9K]3 years ago
3 0

Explanation:

1.    Cesium (Cs) is a group 1 element and it has electronic configuration [Xe] 6s^{1}.

On the other hand, bromine is a group 7 element and it has electronic configuration [Ar] 3d^{10}4s^{2}40^{5}.

Since, Cs is a metal so it will readily lose 1 electron but bromine being a non-metal needs 1 electron to completely fill its orbital.

Hence, bromine atom will attract electrons more strongly.

2.   Sodium (Na) is a a group 1 element and it has electronic configuration 1s^{2}2s^{2}2p^{6}3s^{1}.

Whereas, chlorine is a group 7 element and it has electronic configuration 1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}.

So, sodium is a metal hence, it readily loses its one electron and chlorine being a non-metal will attract one electron in order to completely fill its orbital.

Thus, we can conclude that sodium (Na) atom loses an electron more readily.

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sveta [45]
The answer is D I believe
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3 years ago
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Which equation shows how to solve for enthalpy of solution based on the information in tables?​
Tatiana [17]

Answer: B. triH sol Mgl2= -triHlat+ triHhydr Mg^2+ 2triHhydr^l-

Explanation:

Just did it and it was right

8 0
2 years ago
Write a net ionic equation to show how codeine, c18h21o3n, behaves as a base in water.
Lera25 [3.4K]

Actually, the ionic equation for this is a reversible equation since codeine is a weak base. Any weak base or weak acids do not completely dissociate which makes them a reversible process. The ionic equation for this case is:

<span>C18H21O3N  +  H3O+  </span><=> C18H21O3NH+ +  H2O 

7 0
3 years ago
Place the following covalent bonds in order from least to most polar: a. H-Cl b. H-Br c. H-S d. H-C
timofeeve [1]

Answer:


The Order is as follow,

                                     C-H < S-H < H-Br < H-Cl


Explanation:

                      Polarity depends on the electronegativity difference between two atoms, greater the electronegativity difference, greater will be the polarity of bond and vice versa.


Electronegativity Difference between Hydrogen and other given elements are as follow,


1) C-H;

               E.N of Carbon     = 2.55

               E.N of Hydrogen = 2.20

                                           ------------

               Difference              0.35


2) S-H;

               E.N of Sulfur       = 2.58

               E.N of Hydrogen = 2.20

                                           ------------

               Difference               0.38


3) H-Br;

               E.N of Bromine   = 2.96

               E.N of Hydrogen = 2.20

                                          -------------

               Difference              0.76


4) H-Cl;

               E.N of Chlorine   = 3.16

               E.N of Hydrogen = 2.20

                                           -----------

               Difference               0.96


Hence it is proved that the greatest electronegativity difference is found between H and Chlorine in H-Cl, therefore it is highly polar bond and vice versa.

7 0
3 years ago
Mark the statement as true or false.
alex41 [277]

Answer:

False

Explanation:

The ideas were not proposed

3 0
2 years ago
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