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AlekseyPX
3 years ago
7

Which atom attracts electrons more strongly?

Chemistry
2 answers:
lesya [120]3 years ago
3 0
Bromine attracts electrons more strongly. Cesium is In fact the least electro negative element.

Sodium is more likely to lose an electron because is is less electro negative. Strong electronegativity make the element want more electrons. Sodium has loose electrons with a lower electronegativity so it gives it up easier.
makvit [3.9K]3 years ago
3 0

Explanation:

1.    Cesium (Cs) is a group 1 element and it has electronic configuration [Xe] 6s^{1}.

On the other hand, bromine is a group 7 element and it has electronic configuration [Ar] 3d^{10}4s^{2}40^{5}.

Since, Cs is a metal so it will readily lose 1 electron but bromine being a non-metal needs 1 electron to completely fill its orbital.

Hence, bromine atom will attract electrons more strongly.

2.   Sodium (Na) is a a group 1 element and it has electronic configuration 1s^{2}2s^{2}2p^{6}3s^{1}.

Whereas, chlorine is a group 7 element and it has electronic configuration 1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}.

So, sodium is a metal hence, it readily loses its one electron and chlorine being a non-metal will attract one electron in order to completely fill its orbital.

Thus, we can conclude that sodium (Na) atom loses an electron more readily.

You might be interested in
A) What is the maximum number of grams of nickel bromide that can be produced from the reaction of 67.8 g of nickel with 37.3 g
svetoff [14.1K]

Answer:

The answer to your question is a) 51.07 g of NiBr₂   b) Nickel, 54 g

Explanation:

Data

mass of NiBr₂ = ?

mass if Ni = 67.8 g

mass of Br = 37.3 g

Balanced chemical reaction

                Ni  +  Br₂   ⇒   NiBr₂

Process

1.- Find the atomic mass of the reactants and the molar mass of the product

Ni = 59 g

Br = 79.9 x 2 = 159.8 g

NiBr₂ = 59 + 159.8 = 218.8 g

2.- Find the limiting reactant

theoretical yield  Ni/Br₂ = 59/159.8 = 0.369

experimental yield Ni/Br₂ = 67.8/37.3 = 1.81

The limiting reactant is Bromine because the experimental yield was lower than the theoretical yield.

3.- Calculate the mass of NiBr₂

                    159.8 g of Br₂ --------------- 218.8 g of NiBr₂

                      37.3 g of Br₂ --------------  x

                          x = (37.3 x 218.8) / 159.8

                          x = 8161.24/159.8

                          x = 51.07 g of NiBr₂

4.- Find the excess reactant

The excess reactant is Nickel

                59 g of Ni ---------------- 159.8 g of Br₂

                  x               ----------------  37.3 g of Br₂

                            x = (37.3 x 59)/159.8

                            x = 2200.7/159.8

                            x = 13.77 g of Ni

Excess Ni = 67.8 - 13.77

                 = 54 g

5 0
3 years ago
Marie is working on formulations of a new type of paint that will last longer and be more durable on metal surfaces in order to
Ludmilka [50]

Answer:

The answer is: Applied Chemistry

Explanation:

Apllied Chemistry is a branch of Chemistry that deals with the application and use of Chemistry principles and theories to answer a specific question or solve real world problems. It is aimed at taking Chemistry knowlege from the classroom to the real world. In this example, Marie noticed that a problem had arisen, and that is corrosion of metals, and she set out to apply the principles of Chemistry to make a paint formulation that prevvents corrosion, not just on paper with a bunch of formulas and calculations, but translated into a real life substance. On the other hand, pure Chemistry is the theoretical aspect of Chemistry, where the result of the researches are purely for knowlege and not for real world application.

5 0
3 years ago
A sample of potassium chlorate (15.0 g) is dissolved in 201 g of water at 70 °c with precautions taken to avoid evaporation of a
zlopas [31]
Answer is: unsaturated.
Solubility of potassium chlorate on 70°C is approximately 30 grams in 100 grams of water.
Solubility of potassium chlorate on 70°C is approximately 10 grams in 100 grams of water.
So if dissolve 15 g of potassium chlorate in 201 g of water, there is less salt than it solubility and solution is unsaturated.
4 0
3 years ago
in order to decrease the freezing point of 500. g of water to 1.00° c how many grams of ethylene glycol (C2H602)must be added (K
sesenic [268]

Answer:

if wrong sorry ok????

6 0
2 years ago
From a laboratory process designed to separate water into hydrogen and oxygen gas, a student collected 20.0g of Hydrogen and 158
denis23 [38]

Answer:

it is water 2

Explanation:

3 0
1 year ago
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