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2 years ago

What is the oxidation state of each element in the compound CaS04? Include +or - in your answer as appropriate

Chemistry

1 answer:

borishaifa [10]2 years ago

5 0

Answer:therefore the oxidation state of sulphur is +6 in the compound CaSO4.

Explanation:

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convert 0.876 atm to mmHg. solution: multiply the atm value by 760.0 mmHg/ 1.0 atm 0875 atm x _______ = _______ mm Hg (3 sig fig

Akimi4 [234]

$\tt \dfrac{760~mmHg}{1~atm}\times 0.876~atm=665~mmHg$

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1 year ago

The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be

Stels [109]

Explanation:

1) Initial mass of the Cesium-137= $N_o$ = 180 mg

Mass of Cesium after time t = N

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

Half life of the cesium-137 = $t_{1/2}=30 years[p/tex]where,
[tex]N_o$ = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the isotope

$\lambda$ = rate constant

$N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$N=180mg\times e^{-\frac{0.693}{30 years}\times t}$

Mass that remains after t years.

$N=180 mg\times e^{0.0231 year^{-1}\times t}$

Therefore, the parent isotope remain after one half life will be, 100 grams.

t = 70 years

$N_o=180 mg$

$t_{1/2}= 30 yeras$

$N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}$

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

$N_o=180 mg$

$t_{1/2}= 30 yeras$

N = 1 mg

t = ?

$1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}$

$\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t$

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

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2 years ago

What intermolecular force attracts two non polar molecules to each other

Salsk061 [2.6K]

The intermolecular force that attracts two nonpolar molecules is London dispersion forces, which are also called induced dipole-induced

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2 years ago

Help plz I will give u BRAINLIST

Agata [3.3K]

CS2 + 3O2 = CO2 + 2SO2

1 mole of CS2 gives 1 mole of CO2

12 + 2(32) = 76g of CS2 yields 44 g of CO2

Theoretically 1 g of CS2 yields 44/76 g CO2

Therefore 50 g CS2 should yield 50*44 / 76 = 28.95 g

So % yield = 103.6 % ( which is not possible because you can't create matter from nothing).

The 30g cannot be right . This is experimental err.

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2 years ago

100 points!! Brainliest if correct!!

snow_tiger [21]

Answer A: CO2

Reason: carbon dioxides formula is CO and the number next to it is the molecules

6 0

2 years ago

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