Question

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Answer 1

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

• $dl'=3.621*10^{-4}m$

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

$dl=\frac{Flo}{yA}$

$dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}$

$dl=1.19064778*10^-^4$

Generally the equation for brass cylinder   is mathematically given as

$dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}$

$dl=2.43*10^{-4}$

Therefore Total change in length

$dl'=1.191*10^-^4+(2.43*10^{-4})$

$dl'=3.621*10^{-4}m$

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