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adelina 88 [10]
3 years ago
9

what element is this atom? need the answer in 30 minutes. Feel free to answer the other questions. NEED HELP!

Chemistry
2 answers:
alexandr402 [8]3 years ago
4 0

Answer:

fluorine

Explanation:

I used the number of electrons to determine it.

Westkost [7]3 years ago
4 0

Answer:

Ya, definetly fluorine if you want confirmation!

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In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure
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Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to <u>Dalton's </u><u>Law </u><u>of</u><u> </u><u>Partial </u><u>Pressure</u> the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

P_{total}= P_1+P_2+P_3+\dots +P_n

Here ,

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Hence the total pressure exerted is ,

P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }

Substitute ,

P_{total}=( 400 + 220 + 140 )mm\ of \ Hg

Add ,

P_{total}= 760\ mm\ of \ Hg

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which atom has a change in oxidation number of -3 in the following redox reaction K2Cr2O7 + H2O +S --&gt; KOH + Cr2O3 +SO2
yaroslaw [1]
You have to calculate the oxidation estates of the atoms in each compound.

I will start with K2Cr2O7 because I believe that Cr is the best candidate to reduce its oxidation number in 3 units.

In K2Cr2O7:

- K has oxidation state of 1+, then K2 has a charge of 2* (1+) = 2+.

- O has oxidation state of 2*, then O7 has a charge of 7* (2-) = 14-.

That makes that Cr2 has charge of 14 - 2 = +12, so each Cr has +12/2 = +6 oxidation state.

In Cr2O3:

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So, we have seen that Cr reduced its oxidation state in 3 units, from 6+ to 3+.

Answer: Cr has a change in oxidation number of - 3.
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3 years ago
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