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Burka [1]
3 years ago
10

Please help science question ! thank you have a great day​

Chemistry
2 answers:
jolli1 [7]3 years ago
6 0

Answer:

The particle theory states that the particles of a substance spread out as they gain energy when heated. Thus, the particles take up more space, which means that the density of the substance decreases. It is almost always true that, for each pure sub­ stance (for example, gold), the density of its solid state is greater than the density

Explanation:

puteri [66]3 years ago
4 0

Answer:

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#kpop

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What is the mass number of a carbon atom which has 7 neutrons?
Strike441 [17]

Answer:

Carbon-13

Explanation:

Carbon have three isotopes. Isotopes are the atoms of the same element which has a different number of neutrons. Carbon has 3 isotopes.

Carbon-12 : 6 electrons I 6 protons I 6 neutrons

Carbon-13 : 6 electrons I 6 protons I 7 neutrons

Carbon-14 : 6 electrons I 6 protons I 8 neutrons

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Balance<br> _C2H6() +<br> O2(g) →
nignag [31]

Answer:

2C2H6 + 7O2 → 4 CO2 + 6H20

Explanation:

3 0
3 years ago
Consider the following reaction:2NOBr(g) 2NO(g) + Br2(g)If 0.412 moles of NOBr(g), 0.678 moles of NO, and 0.224 moles of Br2 are
Vaselesa [24]

Answer: K_c=0.0587M

Explanation: The given chemical reaction is:

2NOBr(g)\rightleftharpoons 2NO(g)+Br_2(g)

Equilibrium constant (Kc) in general is written as:

K_c=\frac{[products]}{[reactants]}

Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

K_c=\frac{[NO]^2[Br_2]}{[NOBr]^2}

Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.

[NOBr]=\frac{0.412mol}{10.3L}   = 0.040 M

[NO]=\frac{0.678mol}{10.3L}   = 0.0658 M

[Br_2]=\frac{0.224mol}{10.3L}   = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

K_c=\frac{(0.0658M)^2(0.0217M)}{(0.040M)^2}

K_c=0.0587M

4 0
3 years ago
A solid object has a mass of 104 kg and a volume of 1,278 m3. what is its density?
Sergio [31]
m=104kg\\&#10;V=1,278m^{3}\\\\&#10;d=\frac{m}{V}=\frac{104kg}{1,278m^{3}}\approx81,38\frac{kg}{m^{3}}
7 0
3 years ago
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