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Semenov [28]
3 years ago
13

Suppose you have a liquid solution containing two components, acetone and nonane. The boiling point of pure acetone is 56 C and

the boiling point of pure nonane is 151 C. Your solution has a mole fraction of component acetone equal to 0.1, and the solution behaves as an ideal solution. What is the boiling point of this solution?
Chemistry
1 answer:
Tom [10]3 years ago
4 0

Answer:

The boiling point is somewhere between 56 and 151 °C

Explanation:

Hello,

In this case, it is possible to compute it via rigorous methods in phase equilibrium by using for example a cubic equation of state to model the vapor phase and a suitable excess Gibbs free energy model for the liquid phase, nonetheless, it is an arduous task. In such a way, since the information about both acetone's and nonane's pure boiling points is given as well as acetone's mole fraction, which points out it is about a binary liquid solution, one could make up the boiling point is somewhere between 56 and 151 °C precising that it should be closer to 151 °C as the mixture is 90% nonane and 10% acetone.

Best regards.

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A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )
Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g)   (1)

The reaction rate of equation (1) is given by:

rate = k*[O_{3}][NO]     (2)

<u>We have:</u>

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s  

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

\frac{\Delta[NO_{2}]}{\Delta t} = rate

\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!                                

5 0
3 years ago
How many molecules are there in 4.00 l of oxygen gas at 500.∘ c and 50.0 torr?
Oliga [24]
From  the  ideal  gas law   
pv=nRT , n  is  therefore PV/RT
R is  the
R is  gas  constant =62.364 torr/mol/k
P=500torr
 V=4.00l
T=500+273=773k
n={(500 torr x 4.00l)/(62.364 x773k)}=0.041moles
the  number  of  molecules=moles  x avorgadro costant that is  6.022x10^23)
6.022 x 10^23)  x0.041=2.469 x10^22molecules
3 0
3 years ago
How would you choose an indicator for titrating a strong acid with a strong base?​
Paha777 [63]
A strong acid- strong base titration is performed using a phenolphthalein indicator. Phenolphtalein is chosen because it changes color in a pH range between 8.3 – 10.
6 0
3 years ago
Determine how many grams of solute and solvent you would need to prepare 225 g of 11.9%
Tomtit [17]

Answer:

m_{solute}=26.8g

Explanation:

Hello.

In this case, since the definition of by-mass percent is:

\%m/m=\frac{m_{solute}}{m_{solution}}*100\%

Whereas we know the percent as 11.9 % and the mass of the solution as 225g, so we compute the grams of solute as follows:

m_{solute}=\frac{\%m/m*m_{solution}}{100\%}\\ \\m_{solute}=\frac{11.9\%*225g}{100\%}\\ \\m_{solute}=26.8g

Best regards.

6 0
3 years ago
Why is there an attraction between the two ions in this chemical bond?
ladessa [460]

<u>Answer:</u>

<u>A metallic bond is a force of attraction between charged metal ions and the electrons that are in the delocalized bond, which covers the assembly of ions. A covalent bond is the force of attraction between the nuclei of atoms, and the electrons shared between them. </u>

<u />

<u>Explanation:</u>

<u> A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond can be generated by electrostatic attraction between charged ions (for example, ionic bonds) or by electron sharing (for example, covalent bonds). </u>

I hope this helps you :)

8 0
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