A 500 kg satellite is placed in a circular orbit 6394 km above the surface of the earth. At this elevation, the acceleration of
1 answer:
Answer:
KE = 7.7160 GJ
Explanation:
given data
mass = 500 kg
radius = 6394 km
acceleration of gravity = 4.09 m/s²
orbital speed = 20,000 km/h = 20000 × = 5555.56 m/s
solution
we Kinetic energy is express as
KE = 0.5 × m × v² .................1
here m is mass and v is velocity
put here value and we get
KE = 0.5 × 500 × 5555.56²
KE = 7716061728.400
KE = 7.7160 GJ
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Answer:
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Explanation:
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Answer:
V = 1.1 m/s
Explanation:
given,
mass of railroad car 1 , m = 30,000. kg
travelling at the speed , u = 2.2 m/s
mass of car 2, M = 30,000. kg
initial speed, u' = 0 m/s
final speed of the car after collision, V = ?
using conservation of momentum
m u + M u' = (M+m)V
30000 x 2.2 + 0 = (30000 + 30000) V
60000 V = 66000
V = 1.1 m/s
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