A 500 kg satellite is placed in a circular orbit 6394 km above the surface of the earth. At this elevation, the acceleration of

Question

3 years ago

5

A 500 kg satellite is placed in a circular orbit 6394 km above the surface of the earth. At this elevation, the acceleration of

gravity is 4.09 m/s2. Knowing that its orbital speed is 20,000 km/h, determine the kinetic energy of the satellite. (Round the final answer to two decimal places.)

Physics

1 answer:

Digiron [165] · Answer 1 · 2022-03-26T07:07:36+03:00

Answer:

KE = 7.7160 GJ

Explanation:

given data

mass = 500 kg

radius = 6394 km

acceleration of gravity = 4.09 m/s²

orbital speed = 20,000 km/h = 20000 × $\frac{1000}{3600}$ = 5555.56 m/s

solution

we Kinetic energy is express as

KE = 0.5 × m × v² .................1

here m is mass and v is velocity

put here value and we get

KE = 0.5 × 500 × 5555.56²

KE = 7716061728.400

KE = 7.7160 GJ