Question

A 500 kg satellite is placed in a circular orbit 6394 km above the surface of the earth. At this elevation, the acceleration of gravity is 4.09 m/s2. Knowing that its orbital speed is 20,000 km/h, determine the kinetic energy of the satellite. (Round the final answer to two decimal places.)

Answer 1

Answer:

KE  = 7.7160 GJ

Explanation:

given data

mass = 500 kg

radius = 6394 km

acceleration of gravity = 4.09 m/s²

orbital speed = 20,000 km/h  = 20000 × $\frac{1000}{3600}$  = 5555.56 m/s

solution

we Kinetic energy is express as

KE = 0.5 × m × v²   .................1

here m is mass and v is velocity

put here value and we get

KE = 0.5 × 500 × 5555.56²

KE = 7716061728.400

KE  = 7.7160 GJ