Answer:
m<PQR = 82°
Step-by-step explanation:
In a Rhombus, the diagonals bisect its angles. This means that they divide each the four angles into two equal parts.
Therefore:
(4x - 27)° = (2x + 7)°
Solve for x
4x - 27 = 2x + 7
Collect like terms
4x - 2x = 27 + 7
2x = 34
Divide both sides by 2
2x/2 = 34/2
x = 17
✔️m<PQR = (4x - 27) + (2x + 7)
Plug in the value of x
m<PQR = (4*17 - 27) + (2*17 + 7)
m<PQR = 41 + 41
m<PQR = 82°
The system of equations does not have one solution because the lines will never intersect (last one)
Answer:
x - 3y = 8.
Step-by-step explanation:
Use the point-slope form of the equation of a line:
y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line.
So substituting the given values:
y - (-2) = 1/3(x - 2)
y + 2 = 1/3x - 2/3 Multiply through by 3:
3y + 6 = x - 2
x - 3y = 6 + 2
x - 3y = 8 <---- Standard Form.
Answer:
I would rather do the second option of which uses Compound interest that will give a profit of $47.85
Step-by-step explanation:
In this problem we will be exploring the two formulas
1. simple interest
A= P(1+r*t)
2. compound interest
A= P(1+r/n)^nt
Where A= final amount
P= initial amount
r= rate
t= time.
n= number of periods Compounded
1.given data
P= $600
r= 3%= 3/100= 0.03
t= 2 years
A= 600(1+0.03*2)
A= 600(1+0.06)
A= 600(1.06)
A= $636
Interest = 636-600= $36
2. Given data
P= $600
r= 4%= 4/100= 0.04
n= 24
t= 2
A= 600(1+0.04/24)^24*2
A=600(1+0.0016)^48
A=600(1.0016)^48
A= 600*1.07975
A= 647.85
Interest = 647.85-600= $47.85
Answer:
15120
Step-by-step explanation:
Given:
The number of players at point guard = 10
The number of players at shooting guard = 12
The number of players at small forward = 7
The number of players at power forward = 2
The number of players at center = 9
Then, the number of different teams William could draft is given by:
10 x 12 x 7 x 2 x 9
William could draft 15120 different teams.
