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Elena L [17]
2 years ago
13

A sprinter starting to run from rest, reaches a speed of 8m/s in 2 second, what is the average power needed to accelerate like t

his ?​
Physics
2 answers:
larisa86 [58]2 years ago
7 0

Answer:

okay

Explanation:

power is rate of doing work

power is workdone over time taken

but you don't have information concerning the force

Bogdan [553]2 years ago
5 0

Power = work/time

Work = force x distance

Force = mass x acceleration

So Power = (mass x acceleration x distance) / (time)

acceleration = 8m/s / 2sec  =  4 m/s²

distance = (avg speed) x (time) = 8 m

time = 2 sec

we don't know the runner's mass

Power = (mass) x (4 m/s²) x (8 m) / (2 sec)

<em>Power = (16 x mass in kg) watts</em>

=============================================

Slightly easier way to do it:

Power = (runner's kinetic energy at the end) / (time)

Power = (1/2 m v²) / (time)

Power = (1/2 mass) (64 m²/s²) / (2 sec)

<em>Power = (16 x runner's mass in kg) watts</em>

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ANEK [815]

Answer:

\boxed {\boxed {\sf 412.5 \ kilometers }}

Explanation:

Distance is the product of speed and time.

d=s*t

The speed of the car is 75 kilometers per hour. It traveled for 5.5 hours.

s= 75 \ km/hr \\t= 5.5 \ hr

Substitute the values into the formula.

d= 75 \ km/hr * 5.5 \ hr

Multiply. Note that the hours will cancel each other out.

d= 75 km * 5.5 \\d= 412.5 \ km

The car travelled <u>412.5 kilometers.</u>

5 0
3 years ago
A jet can travel the 6000 km distance between washington,
Andrei [34K]
<span> d = r*t is the basic distance equation
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 t with the tail wind = 6 hr
 r with the tail wind = speed of the plane + wind speed = s + w
 t with the head wind = 7.5 hr
 r with the head wind = speed of the plane - wind speed = s-w
 (s+w)*6 = 6000
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 s - w = 800
</span><span> 2s = 1800
 s = 900 km/h
 s + w = 1000
 w = 100
 Check the anwer by calculating the return trip.
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6 0
3 years ago
Part C Let’s start the analysis by looking at your “extreme usage” cases. Compare the two cases in detail—low usage period versu
Serga [27]

Answer:

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6 0
3 years ago
Una niña está empujando un baúl. El PESO del baúl es de 230 N y el roce es de 50 N, la niña sólo logra ejercer una fuerza de 30
Gre4nikov [31]

Answer:

Su padre necesita aplicar una fuerza de 20 newtons en la misma dirección que la fuerza aplicada por su hija.

Explanation:

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Donde:

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f - Fuerza de rozamiento estático máximo, medida en newtons.

Se despeja la fuerza externa:

P = f

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P = 50\,N

Si la niña solo logra ejercer una fuerza de 30 newtons, su padre necesita aplicar una fuerza de 20 newtons paralela a aquella fuerza.

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Stells [14]
This is simple question and easy to understand.
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Then you gonna place all your values according to you have in the formula as shown then solve for f.
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8 0
3 years ago
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