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Elena L [17]
2 years ago
13

A sprinter starting to run from rest, reaches a speed of 8m/s in 2 second, what is the average power needed to accelerate like t

his ?​
Physics
2 answers:
larisa86 [58]2 years ago
7 0

Answer:

okay

Explanation:

power is rate of doing work

power is workdone over time taken

but you don't have information concerning the force

Bogdan [553]2 years ago
5 0

Power = work/time

Work = force x distance

Force = mass x acceleration

So Power = (mass x acceleration x distance) / (time)

acceleration = 8m/s / 2sec  =  4 m/s²

distance = (avg speed) x (time) = 8 m

time = 2 sec

we don't know the runner's mass

Power = (mass) x (4 m/s²) x (8 m) / (2 sec)

<em>Power = (16 x mass in kg) watts</em>

=============================================

Slightly easier way to do it:

Power = (runner's kinetic energy at the end) / (time)

Power = (1/2 m v²) / (time)

Power = (1/2 mass) (64 m²/s²) / (2 sec)

<em>Power = (16 x runner's mass in kg) watts</em>

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kicyunya [14]

Answer:

Heat acclimatization :

   It is the biological adaptations or we can say that it coverts according to the present environment.It also reduce the strain and maintain the normal temperature and heart rate.Heat acclimatization also increase the comfort and reduce all the mental strain and also protect out liver ,muscles ,kidneys and brain fro the injury.

5 0
3 years ago
Sawyer launches his 180 kg raft on the Mississippi River by pushing on it with a force of 75N. How long must Sawyer push on the
Daniel [21]

Answer: 4.8 s

Explanation:

We have the following data:

m=180 kg the mass of the raft

F=75 N the force applied by Sawyer

V=2 m/s the raft's final speed

V_{o}=0 m/s the raft's initial speed (assuming it starts from rest)

We have to find the time t

Well, according to Newton's second law of motion we have:

F=m.a (1)

Where a is the acceleration, which can be expressed as:

a=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{t-t_{o}} (2)

Substituting (2) in (1):

F=m\frac{V-V_{o}}{t-t_{o}} (3)

Where t_{o}=0

Isolating t from (3):

t=\frac{m(V-V_{o})}{F} (4)

t=\frac{180 kg(2 m/s-0 m/s)}{75 N}

Finally:

t=4.8 s

6 0
3 years ago
The process of converting a liquid to a gas is known as _____.
Sloan [31]

This is called vaporization.




hope this helps :)

8 0
2 years ago
Read 2 more answers
A plane designed for vertical takeoff has a mass of 8.0 × 10³ kg. Find the net work done by all forces on the plane as it accele
artcher [175]

Answer:

<em>the net work done after starting from rest is =  2.4 × 10⁵ J</em>

Explanation:

Work: Work can be defined as the product of force and distance. The fundamental unit of work is Joules (J),  The unit of Energy is Joules (J), as such Energy and work are interchangeable during calculation, This is illustrated below

E = W = 1/2mv².......................... Equation 1

Where m = mass of the plane, v = velocity of the plane, E = Energy, W = work done.

v² = u² + 2as ................................. Equation 2.

Where v = final velocity of the plane, u = initial velocity of the plane, a = acceleration of the plane, distance of the plane.

<em>Given: a = 1.0 m/s², s = 30 m, u = 0 m/s (at rest)</em>

<em>Substituting these values into equation 2</em>

<em>v² = 0² +2×1×30</em>

<em>v² = 60</em>

<em>v = √60</em>

<em>v = 7.75 m/s</em>

Also given: m = 8.0 × 10³ kg, and v = 7.75 m/s

<em>Substituting these values into equation 1,</em>

<em>W = 1/2(8.0×10³)(7.75)²</em>

<em>W = (4.0×10³)(60)</em>

W = 240 × 10³ J

<em>W = 2.4 × 10⁵ J</em>

<em>Therefore the net work done after starting from rest is =  2.4 × 10⁵ J</em>

4 0
3 years ago
Which of the following is true about the mass of an object?
Butoxors [25]
I believe it is the first one
5 0
2 years ago
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