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larisa [96]
3 years ago
5

A rod (length = 80 cm) with a rectangular cross section (1.5 mm × 2.0 mm) has a resistance of 0.20 Ω. What is the resistivity of

the material used to make the rod?
Physics
1 answer:
Andru [333]3 years ago
7 0

Answer:

The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m

Explanation:

R= 0.2 Ω

L= 0.8 m

S= 1.5mm*2mm= 3 mm² = 3 * 10⁻⁶ m²

ρ = (R*S)/L

ρ= 7.5 * 10⁻⁷ Ω.m

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Vector A has magnitude 13.0 m and vector B has magnitude 16.0 m. The scalar product A.B is 116 m2. What is the magnitude of the
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Answer:

\text{Vector product}=172.66\ m^2

Explanation:

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6 0
3 years ago
A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9
Black_prince [1.1K]

Answer:

C = 46.891 \mu F

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

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s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

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C = \frac{Q_C}{ v_{rms}^2 \omega}

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