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larisa [96]
3 years ago
5

A rod (length = 80 cm) with a rectangular cross section (1.5 mm × 2.0 mm) has a resistance of 0.20 Ω. What is the resistivity of

the material used to make the rod?
Physics
1 answer:
Andru [333]3 years ago
7 0

Answer:

The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m

Explanation:

R= 0.2 Ω

L= 0.8 m

S= 1.5mm*2mm= 3 mm² = 3 * 10⁻⁶ m²

ρ = (R*S)/L

ρ= 7.5 * 10⁻⁷ Ω.m

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A sample of a gas in a rigid container at 30. 0°c and 2. 00 atm has its temperature increased to 40. 0°c. What will be the new p
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Answer:

2.066 atm

Explanation:

PV = nRT      increase T    volume and n and R remain constant

30 C = 303.15 K      40 C = 313.15

P  prop to T      new P   will be   313.15/303.15 * 2 atm = 2.066 atm

8 0
2 years ago
What is the temperature
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The temperature is the degree on intensity of heat in a specific place. Usually, the temperature of thermic neutrality is 70 Fahrenheit or 21 Celsius.

Hope this Helps! :)
8 0
4 years ago
Read 2 more answers
One afternoon, a couple walks three-fourths of the way around a circular lake, the radius of which is 2.51 km. they start at the
Marysya12 [62]
(a) Since the lake has a circular shape, the distance they traveled is exactly 3/4 of a circumference. The radius of the lake is 2.51 km, and the circumference is given by 2\pi r, therefore the distance covered is
d= \frac{3}{4} (2 \pi r) = \frac{3}{2} \pi (2.51 km)=11.82 km

(b) We can consider the lake to be on a xy-plane with the origin of the axes being at the center of the lake. In this system of coordinates, the starting point of the motion is at the west side of the lake, so at coordinates (-2.51 km,0). The final point is after 3/4 of circumference, therefore at the north side, at coordinates (0, 2.51 km).
So we can calculate the magnitude of the displacement as
d= \sqrt{(x_f-x_i)^2+(y_f-y_i)^2} = \sqrt{(0-(-2.51))^2+(2.51-0)^2}=
=3.55 km

(c) Considering only the initial and final point of the motion, the couple moved 2.51 km north (on the x-axis) and 2.51 km east (on the y-axis). Therefore, we can calculate the angle of the displacement with respect to the east direction:
\tan \alpha =  \frac{\Delta y}{\Delta x} = \frac{2.51 km}{2.51 km}=1
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\alpha=45^{\circ}
3 0
3 years ago
A 1650kg car accelerates at a rate of 4.0 m/s2. How much force is the car’s engine producing?
Hitman42 [59]
F = M A

Force = (mass) x (acceleration)

= (1,650 kg) (4 m/s²) = 6,600 kg-m/s² = 6,600 Newtons
4 0
3 years ago
Which has more momentum: a 5000 kg truck moving at 10 m/s or a sports car with a
Anna [14]

Answer:

The sports car has more momentum.

Explanation:

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Sports car: P = mv = 1200 kg × 50 m/sec = 60,000 kg-m/sec

4 0
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