Answer: g = 10.0 m/s/s
Explanation:
For a simple pendulum, provided that the angle between the lowest and highest point of his trajectory be small, the oscillation period is given by the following expression:
T = 2π √L/g , where L = pendulum length, g= accelleration of gravity.
We can also define the period, as the time needed to complete a full swing, so from the measured values, we can conclude the following :
T = 140 sec/ 101 cycles = 1.39 sec
Equating both definitions for T, we can solve for g, as follows:
g = 4 π² L / T² = 4π². 0.49 m / (1.39)² = 10.0 m/s/s
( (77/4) + 76/2 )/2 = 28.625 km/h is what i got
Actually Welcome to the Concept of the Projectile Motion.
Since, here given that, vertical velocity= 50m/s
we know that u*sin(theta) = vertical velocity
so the time taken to reach the maximum height or the time of Ascent is equal to
T = Usin(theta) ÷ g, here g = 9.8 m/s^2
so we get as,
T = 50/9.8
T = 5.10 seconds
thus the time taken to reach max height is 5.10 seconds.
F = 750 N (Force)
d = 10 m (displacement
)
t = 25 s (time)
L = ? (Mechanical work
) = (Energy)
P = ? (Power)
Solve:
L = F × d = 750 × 10 = 7500 Joules
P = L / t = 7500 / 25 = 300 Watts
Answer:
Nuclease is the answer I know
I hope this is the answer
