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denis23 [38]
3 years ago
9

A temperature of 20°C is equivalent to approximately

Physics
2 answers:
igomit [66]3 years ago
8 0
Its the answer D. 68°F
algol133 years ago
7 0

A temperature of 20°C is equivalent to approximately

A. 32°F.

B. –6°F.

C. 136°F.

D. 68°F.

The correct answer for this question is D. 68°F

~ Please mark Brainiest :)

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What is the net force on a car if the force of friction is 15 N and the forward force due to the engine is 20 N?
anygoal [31]
D. 35n forwards....................
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3 years ago
How does gravitational pull affect planets with the same mass but different distance from the sun?
Yakvenalex [24]

Answer:

it just pulls them at the same time

Explanation:

5 0
3 years ago
The momentum of an object is 35 kg•m/s and it is travelling at a speed of 10 m/s.
Naddik [55]

Answer:

{ \bf{momentum = mass \times velocity}} \\  \\ { \tt{35 = m \times 10}} \\ { \tt{mass = 3.5 \: kg}}

4 0
2 years ago
A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can
Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

\mu is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

v=85 mph \cdot \frac{1609}{3600}=38.0 m/s is the speed

And solving for \mu, we find the coefficient of friction required to keep the car in circular motion:

\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196

Learn more about circular motion:

brainly.com/question/2562955  

brainly.com/question/6372960  

#LearnwithBrainly

8 0
3 years ago
A water wave has a speed of 23.0 meters/second. If the wave’s frequency is 0.0680 hertz, what is the wavelength?
tankabanditka [31]
     Using the Fundamental Equation of Wave, we have:

v=\lambda f \\ \lambda= \frac{23}{0.068}  \\ \boxed {\lambda \approx 338m}

Letter B
3 0
3 years ago
Read 2 more answers
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