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denis23 [38]
3 years ago
9

A temperature of 20°C is equivalent to approximately

Physics
2 answers:
igomit [66]3 years ago
8 0
Its the answer D. 68°F
algol133 years ago
7 0

A temperature of 20°C is equivalent to approximately

A. 32°F.

B. –6°F.

C. 136°F.

D. 68°F.

The correct answer for this question is D. 68°F

~ Please mark Brainiest :)

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What is the weight of a 10kg Mass pushed by a 5 N force
babunello [35]

As long as it's on Earth, 10kg of mass weighs <em>98.1 Newtons.</em>  

It doesn't matter if it's being pushed, pulled, mashed, heated on the stove, frozen in a snowdrift, painted black, shot from a cannon, hung from the ceiling, sunk in mud, licked by a puppy, or just left sitting in the back of the drawer.  None of these has any effect on its weight.  

To change its weight, you'd have to either change its mass ... cut a piece off of it or glue another piece onto it ...  or change the strength of gravity ... like take it to the moon or to another planet.

6 0
3 years ago
The best way to deal with anger is to
Bad White [126]
1.think before you speak
2.once your calm express your anger
3.exercise
4.take time out
5.identify possible solutions
6.stick with I statements (to avoid placing the blame)
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3 0
3 years ago
Match the numbers
grandymaker [24]

-- Photographic film detects radiation.
-- Gas occupies the whole container.
-- The Geiger counter is used to detect and measure
       the intensity of radiation.
-- An atom is the <span>smallest particle to retain characteristics
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-- The atomic mass is the mass of the protons and neutrons in the atom.</span>
    (The electrons hardly make any difference. One proton or neutron has
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8 0
3 years ago
Una esfera de radio 0.4m tiene una masa de 300kg, se desea sumergir en agua para saber si flota o no. En este ejercicio use la d
iragen [17]

Answer:

La esfera no flotará pero se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.

Explanation:

De la pregunta anterior, se obtuvieron los siguientes datos:

Radio (r) de la esfera = 0,4 m

Masa de esfera = 300 Kg

Densidad del agua = 1000 Kg / m³

A continuación, determinaremos el volumen de la esfera. Esto se puede obtener de la siguiente manera:

Radio (r) de la esfera = 0,4 m

Pi (π) = 3,14

Volumen (V) de la esfera =?

V = 4/3 πr³

V = 4/3 × 3,14 × 0,4³

V = 12,56 / 3 × 0,064

V = 0,27 m³

A continuación, determinaremos la densidad de la esfera. Esto se puede obtener como se ilustra a continuación:

Masa de esfera = 300 Kg

Volumen de esfera = 0,27 m³

Densidad de esfera =?

Densidad = masa / volumen

Densidad de la esfera = 300 / 0,27

Densidad de la esfera = 1111,11 Kg / m³

Comparando la densidad del agua y la de la esfera.

Sustancia >>>>>>> Densidad

Agua >>>>>>>>>>> 1000 Kg / m³

Esfera >>>>>>>>>> 1111,11 Kg / m³

De la ilustración anterior, podemos ver que la densidad de la esfera es mayor que la del agua.

Por lo tanto, la esfera no flotará sino que se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.

4 0
3 years ago
What is the<br> power of a light<br> bulb with 8V and<br> a current of 2A?
astra-53 [7]

Answer:

16 Watts

Explanation:

P = VI, where V is the voltage and I is the current (of the lightbulb)

V = 8 volts, I = 2 amps

P = 8 * 2 = 16 Watts

3 0
3 years ago
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