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Alinara [238K]
2 years ago
7

A square loop of wire with a small resistance is moved with constant speed from a field free region into a region of uniform B f

ield (B is constant in time) and then back into a field free region to the left. The self inductance of the loop is negligible. True While the loop is entirely in the field, the emf in the loop is zero. False When entering the field the coil experiences a magnetic force to the left. False When leaving the field the coil experiences a magnetic force to the right. True Upon entering the field, a clockwise current flows in the loop.
Physics
1 answer:
Anvisha [2.4K]2 years ago
5 0

Answer:

False, True, False, True

Explanation:

Given a square loop of a wire having a small resistance and moving with a constant sped from the free region to a region having a region having a uniform field B.  It is then moved back to the left in the free field region.

For the following statements :

While the loop is entirely in the field, the emf in the loop is zero.  -- TRUE

The emf of the coil is zero when the coil moves into the field from a free region field to a uniform field region field.

When entering the field the coil experiences a magnetic force to the left   ---- FALSE

According to the Lenz law, a loop entering the field opposes it and moves towards the right.

When leaving the field the coil experiences a magnetic force to the right. --- TRUE

Upon entering the field, a clockwise current flows in the loop.  ---- TRUE

In the field the coil or the loop tries to oppose the magnetic field and forces the current in the loop to move in a clockwise direction.

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How much kinetic energy does a 50 kg object have if its moving at a velocity of 2 m/s?
bulgar [2K]

Answer:

C) 100 joules

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where m is the mass of the object and v its speed.

In this problem, we have an object of mass m = 50 kg and v = 2 m/s, so by using the formula we can find its kinetic energy:

K=\frac{1}{2}(50 kg)(2 m/s)^2=100 J

3 0
2 years ago
An automatic dryer spins wet clothes at an angular speed of 5.2 rad/s. Starting from rest, the dryer reaches its operating speed
Dvinal [7]
<h2>Time taken by dryer to come up to speed is 1.625 seconds.</h2>

Explanation:

We have equation of motion v = u + at

     Initial velocity, u =  0 rad/s

     Final velocity, v = 5.2 rad/s    

     Time, t = ?

     Acceleration, a = 3.2 rad/s²

     Substituting

                      v = u + at  

                      5.2 = 0 + 3.2 x t

                      t = 1.625 s

Time taken by dryer to come up to speed is 1.625 seconds.

6 0
3 years ago
Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 45.0 mph . Beth leaves Los A
WARRIOR [948]

Answer:

a.Beth

b.2232 s

Explanation:

We are given that

Distance,d=400 mi

Speed of Alan,v=45 mph

Speed of Beth,v'=55 mph

a.Time =\frac{distance}{speed}

Using the formula

Time taken by Alan=\frac{400}{45}=8.89 hr

Time taken by Beth=\frac{400}{55}=7.27hr

Alan will reach San Francisco at 4:53 PM

Beth will reach San Francisco at 4:16 PM

Beth will reach before Alan.

b.Difference between time=8.89-7.27=1.62 hr

t=1.62 hr

1.62-1=0.62 hr

0.62 hr=0.62\times 60\times 60=2232 s

Hence, Beth has to wait 2232 s for Alan to arrive .

6 0
3 years ago
In what direction must the current I2 flow in the straight wire in order to create a field at the center of the loop in the dire
guajiro [1.7K]

Answer:

Right to left

Explanation:

From right hand thumb rule, the magnetic field at the centre of loop points out of the plane of paper. Thus the straight wire current should create magnetic field into the plane of paper at the centre. Hence the direction of current in long wire should be from right to left

6 0
3 years ago
One particular descent goes from 2100m to 1600m. Assuming work done against friction is 90% of the potential energy change of th
alisha [4.7K]

Answer:

1/2 M V^2 = .1 M g H       where 10% of PE goes into KE

V^2 = .2 g H = .2 * 9.8 * (2100 - 1600) = 980 m^2 / s^2

V = 31.1 m/s       increase in speed during descent

1 km / hr = 1000 m / 3600 sec = .278 m/s

V = 31.1 m/s / (.278 m/s / km /hr)= 112 km/hr

7 0
1 year ago
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