1.

i have a mixture of a tomato sauce, sugar, and carrots i bring a magnet close by. what does the magnet pick up and what is left

MrRissso [65]

Answer:

None.

Explanation:

Magnets only pick up metal, so in that case the magnet will not pick up any.

3 0

4 years ago

a water heater contains 58 Gal of water. How many kilowatt-hours of energy are necessary to heat the water in the water heater b

Citrus2011 [14]

Answer:

6.45 KWh

Explanation:

Data given:

amount of water = 58 gallon

Convert gallons to L

1 gallon = 3.78541 L

58 gallon = 58 x 3.78541 = 220 L

change in temperature = 25 °C

kilowatt-hours of energy = ?

Solution:

First we have to change volume of water into mass

following formula will use

m = d x v . . . . . . (1)

as we know

density of water = 1000 g/L

Put values in equation 1

m = 1000 g/L x 220 L

m = 220000

To calculate heat we use following formula

Q = m.c.ΔT . . . . . . . . . . (2)

Where

m= mass

c = specific heat of water

specific heat of water = 4.186 J/g °C

ΔT = change in temperature

Put values in equation 1

Q = 220,000 g x 4.186 J/g °C x 25 °C

Q = 23023000 J

As we need this value in kilowatt-hours of energy so we convert J to KWh

1 J = 2.8 x 10⁻⁷ KWh

23023000 J = X KWh

Do cross multiplication

KWh = 23023000 J x 2.8 x 10⁻⁷ KWh / 1 J

KWh = 6.45 KWh

6.45 KWh (kilowatt-hours) of energy are needed to heat the water in the water heater.

3 0

3 years ago

Please answer this. List the three most abundant minerals in this bottle of mineral water.

Lisa [10]

The three most abundant minerals in a water bottle are calcium, potassium, and magnesium. {etc}

6 0

3 years ago

What comes first in a thunderstorm?

Vedmedyk [2.9K]

It's the sound before the lightning because sound travels faster than light.

8 0

3 years ago

A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

4 0

3 years ago