Which element or compound has lost electrons in this oxidation-reduction reaction? 4li 2coo → 2co 2li2o a. coo b. li2o c. li d
1 answer:
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Data:
m (<span>Sample Mass) = ?
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (
)
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
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Molar Mass
= 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:
Solving:
Answer:
By approximation would be letter D) <span>337.2 g</span>
m (<span>Sample Mass) = ?
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass
</span>
Formula:
Solving:
Answer:
By approximation would be letter D) <span>337.2 g</span>
Answer:
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yea... im just gonna do two fo them, i think u can figure it out from there
Explanation:
