What elements comprise the largest portion of Earth's atmosphere?
1 answer:
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Answer:
4. 1.18 mol·L⁻¹
14. See below.
Explanation:
4. Dilution calculation
V₁c₁ = V₂c₂
Data:
V₁ = 200 mL; c₁ = 5.6 mol·L⁻¹
V₂ = 950 mL; c₂ = ?
Calculation:
c₂ = c₁ × V₁/V₂
c₂ = 5.6 mol·L⁻¹ × (200/950) = 1.18 mol·L⁻¹
The new concentration is 1.18 mol·L⁻¹ .
14. Boyle's Law graphs
We can write Boyle's Law as
pV = k or p = k/V or V= k/p
p and V are inversely related.
(a) As pressure increases, volume decreases. Thus, a graph of V vs p is a hyperbola.
(b) p = k/V =k(1/V)
1/V = (1/k)p
y = m x + 0
A graph of 1/V vs p is a straight line.
Answer: The new volume of gas is 28.5 L
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 1.00 atm (at STP)
= final pressure of gas = 102.6 kPa = 1.01 atm (1 kPa= 0.0098 atm)
= initial volume of gas = 10.0 L
= final volume of gas = ?
= initial temperature of gas =
(STP)
= final temperature of gas =
Now put all the given values in the above equation, we get:
The new volume of gas is 28.5 L