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2 years ago

A sample of 5.72 g of liquid 1-propanol, C, H, O, is combustod with 43.4 g of oxygen gas, Carbon dioxide and water are

Chemistry

1 answer:

bekas [8.4K]2 years ago

6 0

Answer:

2C3H8O + 9O2 ==> 6CO2 + 8H2O ... balanced equation

moles propanol = 5.26 g x 1 mol/60.1 g = 0.0875 moles

moles O2 = 31.8 g x 1 mol/31.9 g = 0.997 moles O2

Propanol is limiting based on the mol ratio in balance equation of 2 : 9

To find mass of O2 (excess reagent) left over, we will first find moles O2 used up.

moles O2 used = 0.0875 mol propanol x 9 mol O2/2 mol propanol = 0.394 moles O2 used

moles O2 left over = 0.997 mol - 0.394 mol = 0.603 mol O2 left

mass O2 left = 0.603 mol O2 x 32 g/mol = 19.3 g O2 left over

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In 1990, the northern spotted owl was listed as endangered. Because of this, millions of acres of forests in the Pacific

Gwar [14]

Answer:

the endangered spices act

Explanation: The US Endangered Species Act (ESA) is our nation's most effective law to protect at-risk species from extinction, with a stellar success rate: 99% of species listed on it have avoided extinction.

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3 years ago

What do you think the axis of rotation means?

larisa86 [58]

Answer:

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Explanation:

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3 years ago

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

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Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

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3 years ago

Serine has pka1 = 2.21 and pka2 = 9.15. use the henderson-hasselbalch equation to calculate the ratio neutral form/protonated fo

malfutka [58]

Calculate the ratio by using Henderson-Hasselbalch equation:

pH = pKa + log [neutral form] / Protonated form

3.05 = 2.21 + log [neutral form] / [Protonated form]

3.05 - 2.21 = log [neutral form] / [Protonated form]

0.84 = log [neutral form] / [Protonated form]

[neutral form] / [protonated form] = anti log 0.84 = 6.91

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3 years ago

Which of the following does NOT involve a change of state? a. pouring water into a vacuum-insulated bottle b. sublimation of dry

Elena L [17]

<h2> The correct option is (a).</h2>

Explanation:

There is no change of state in pouring water into a vacuum insulated bottle as the vacuum created inside the bottle only reduces the time limit for the transfer of heat by conduction and convection.
It helps the content filled in the bottle to be hot and cool for a longer time.

Hence, option (a) is correct.

Rest of the options (b), (c), (d), (e) is not correct because of the following reasons:

In the sublimation of dry ice, the dry ice (solid-state) is changed to the vapour form.
In the freezing of water, the liquid state is changed to solid-state.
During the vaporization of alcohol, the liquid state is changed to the vapour form.
During the melting of ice, the solid-state is changed to the liquid state.

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3 years ago