A sample of 5.72 g of liquid 1-propanol, C, H, O, is combustod with 43.4 g of oxygen gas, Carbon dioxide and water are
1 answer:
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Answer:
Work done = 600 J
Power used = 60 W
Explanation:
Given:
Force acting on the box is,
Displacement of the box is,
Time taken for the work,
Now, we know that, work is said to be done by a force only when there is displacement caused by the force in its direction.
Here, the force acting on the box causes a displacement of 30 m in its direction. So, work done is equal to the product of force and displacement caused.
Therefore, work done on the box is given as:
Therefore, the work done is 600 J.
Now, we know that, power is given as work done per unit time.
So, power used is given as:
Therefore, the power used is 60 W.
Explanation:
Relation between pressure, latent heat of fusion, and change in volume is as follows.
Also,
where, is the difference in specific volumes.
Hence,
As, = 22.0 J/mol K
And, ...... (1)
where, = density of water
= density of ice
M = molar mass of water =
Therefore, using formula in equation (1) we will calculate the volume of fusion as follows.
=
=
Therefore, calculate the required pressure as follows.
=
or, = 145 bar/K
Hence, for change of 1 degree pressure the decrease is 145 bar and for 4.7 degree change dP =
= 681.5 bar
Thus, we can conclude that pressure should be increased by 681.5 bar to cause 4.7 degree change in melting point.