1. Using a triple beam balance and a graduated cylinder, a student collected data on a sample of an

Chemistry

1 answer:

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

d = 2.8 g/mL

Explanation:

Given data:

Mass of sample = 67.9 g

Volume of water = 28.0 mL

Volume of water + sample = 52.0 mL

Density of sample = ?

Solution;

Density is equal to the mass of substance over volume of substance.

Formula:

d = m/v

d = density

m = mass

v= volume

Now we will calculate the volume of sample.

Volume of sample = (volume of water+ sample) - volume of water

Volume of sample = 52.0 mL - 28.0 mL

Volume of sample = 24.0 mL

Now we will calculate the density.

d =67.9 g /24.0 mL

d = 2.8 g/mL

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If copper carbonate system is heated for too short a time, what will you notice for mass percent of copper be too large or too s

sammy [17]

Answer:

The mass percent of copper as element is the same.

Explanation:

First of all we need the reaction that is presented below:

$CuCO_{3 (s)} +Heat$ → $CuO_{(s)} + CO_{2 (g)}$

The mass percent of copper (Cu) as element is the same because of during the reaction the element only transform its nature from copper carbonate ( $CuCO_{3 (s)}$ ) to copper oxide ( $CuO_{(s)}$ ), the latter is a solid and will remain in the system.

On the other hand, you will note that the global percentage mass will be small because of the reaction produce ( $CO_{2 (g)}$ ) that is a gas and this one will escape for the system.