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a_sh-v [17]
2 years ago
8

A particle is moving along a projectile path at an initial height of 160 feet with an initial speed of 144 feet per second. this

can be represented by the function h(t) = −16t2 144t 160. what is the maximum height of the particle? 128 feet 224 feet 272 feet 484 feet
Business
1 answer:
galina1969 [7]2 years ago
3 0

A function assigns values. The maximum height of the particle is 484 ft.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given that the function of the height of the particle is h(t) = −16t²+144t+160.

Now, to find the maximum of the function we need to differentiate the function, and then equate it with zero to find the value of t at which the height will be maximum.

h(t)=-16t^2+144t+160\\\\\dfrac{dh}{dt}=-16(2t)+144\\\\\dfrac{dh}{dt}=-32t+144

Now, equate the function with 0, we will get,

0=-32t+144\\t = 4.5

Further, plug in the value of t as 4.5 to get the maximum height.

h(t)=-16t^2+144t+160\\\\h(4.5)=-16(4.5^2)+144(4.5)+160\\\\h(4.5)= 484\rm\ ft

Thus, the maximum height of the particle is 484 ft.

Learn more about Function:

brainly.com/question/5245372

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To find the NPV using a financial calacutor:

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I hope my answer helps you

7 0
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Answer: The answer is given below

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