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Stels [109]
3 years ago
11

Suppose that it takes a simple pendulum 1.2 seconds to swing from its leftmost point to its rightmost point. what is the period

of the pendulum
Physics
1 answer:
Mariana [72]3 years ago
7 0

The time period of the simple pendulum is 2.4 seconds.

Given the data in the question;

  • Time taken to swing from leftmost point to rightmost point; t = 1.2s
  • Period of the pendulum; T = \ ?

<h3>What is Period?</h3>

Period is the time needed for a complete cycle of vibration to pass a given point.

Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.

Now, if it took the pendulum 1.2s to swing from leftmost point to rightmost point, it will also take the pendulum 1.2s to swing back to its original position( leftmost point )

Hence,

T = time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.

T = 1.2s + 1.2s\\\\T = 2.4s

Therefore, the time period of the simple pendulum is 2.4 seconds.

Learn more about Time Period: brainly.com/question/27135322

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Complete Question:

A heat engine with 0.300 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 500 K . The gas goes through the following closed cycle: - Isothermal expansion to 5000 cm3. - Isochoric cooling to 400 K . - Isothermal compression to 1000 cm3. - Isochoric heating to 500 K .

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Explanation:

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W = nRT ln(V/V)

But  ln(V/V) = ln 1 = 0

Work done, W₂ = 0 Joules

Isothermal Compression to 1000 cm³

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W = nRT ln(V₂/V₁)

W = 0.3 * 8.314 * 400 ln(1000/5000)

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a) Work done for 1 cycle

W = W₁ + W₂ + W₃ + W₄

W = 2007.13 + 0 + 0 -1605+0

W = 402.13 Joules

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Heat absorbed = Work done due to thermal expansion = 2007.13 J

Thermal efficiency = 402.13/2007.13

Thermal efficiency = 0.2

Thermal efficiency = 0.2 * 100% = 20 %

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