Suppose that it takes a simple pendulum 1.2 seconds to swing from its leftmost point to its rightmost point. what is the period
1 answer:
The time period of the simple pendulum is 2.4 seconds.
Given the data in the question;
- Time taken to swing from leftmost point to rightmost point;
- Period of the pendulum;
Period is the time needed for a complete cycle of vibration to pass a given point.
Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.
Now, if it took the pendulum to swing from leftmost point to rightmost point, it will also take the pendulum
to swing back to its original position( leftmost point )
Hence,
= time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.
Therefore, the time period of the simple pendulum is 2.4 seconds.
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Looking at the scenario, you can tell that this is a Type 1 Projectile, or a horizontal projectile. You would need a couple of things before you can solve this problem.
First you need to take a look at your given:
Vix = 2.87 m/s (Horizontal velocity)
dx = 5.32m (Horizontal distance)
What you need is your vertical distance or your height. The standard formula for projectile displacement is:
Where:
vi = initial velocity
g = Acceleration due to gravity = 9.8m/s^2
t = time
To specifically get the vertical distance you just need to put in the y-components. Now remember that initially, for a horizontal projectile, there is not vertical movement, only forward. So your vi = om/s which will leave you with the equation:
Your new formula would then be:
But if you look at your problem, you can see that there is no time given. With what was given to you, you can solve it by deriving it from the x component formula:
Plug in what you know and solve for what you don't know.
Your time is then 1.85s.
Now that you know the time, you can now solve for your vertical distance/displacement:
The cliff was then 16.77m high.
First you need to take a look at your given:
Vix = 2.87 m/s (Horizontal velocity)
dx = 5.32m (Horizontal distance)
What you need is your vertical distance or your height. The standard formula for projectile displacement is:
Where:
vi = initial velocity
g = Acceleration due to gravity = 9.8m/s^2
t = time
To specifically get the vertical distance you just need to put in the y-components. Now remember that initially, for a horizontal projectile, there is not vertical movement, only forward. So your vi = om/s which will leave you with the equation:
Your new formula would then be:
But if you look at your problem, you can see that there is no time given. With what was given to you, you can solve it by deriving it from the x component formula:
Plug in what you know and solve for what you don't know.
Your time is then 1.85s.
Now that you know the time, you can now solve for your vertical distance/displacement:
The cliff was then 16.77m high.