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otez555 [7]
3 years ago
14

Uses of hydrometer in points​

Physics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water

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Which statement best describes a parallel circuit?
Anni [7]

Answer:a

Explanation:

Current increases as resistors are taken away

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4 years ago
What is the tendency of a material to oppose the flow of charge?
elena55 [62]

I think the answer is Resistance.  If the link i posted int he comment is right.

8 0
4 years ago
(a) a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerte
Musya8 [376]

The dimension of force, F is ML/T².

<h3>What is force?</h3>

Force is a push o push agent which causes a change in the state of rest or motion of an object.

From a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerted on the object and inversely proportional to its mass.

Mathematically; acceleration ∝ F/m

F = ma

dimension of Mass = M

dimension of acceleration = L/T²

dimension of force, F = ML/T²

In conclusion, the dimension of force is obtained from the dimensions of mass and acceleration.

Learn more about dimension of force at: brainly.com/question/28243574

#SPJ1

5 0
2 years ago
Help me with this please
Jobisdone [24]

Answer:

Option D- 1,2 and 3

Explanation:

Gravity always acts on an object irrespective of height

4 0
3 years ago
Read 2 more answers
Find the de Broglie wavelength of the following. (a) a 4-MeV proton 14.3 Correct: Your answer is correct. fm (b) a 40-GeV electr
kherson [118]

a) de Broglie wavelength of a 4-MeV proton: 14.3 fm

b) de Broglie wavelength of a 40-GeV electron: 0.031 fm

Explanation:

a)

The de Broglie wavelength of an object is given by

\lambda=\frac{h}{p} (1)

where

h is the Planck constant

p is the momentum of the particle

Here we want to find the de Broglie wavelength of a 4-MeV proton. The rest of mass of the proton in MeV is

m_0 = 938 MeV

And since 4MeV, this means that the proton is non-relativistic. So its kinetic energy is related to its momentum by

E=\frac{p^2}{2m}

which means

p=\sqrt{2Em}

where

E=4 MeV \cdot 10^6 eV/MeV \cdot 1.6\cdot 10^{-19] J/eV=6.4\cdot 10^{-13} J is the kinetic energy

m=1.67\cdot 10^{-27} kg is the proton mass

Substituting, we find

\lambda=\frac{h}{\sqrt{2Em}}=\frac{6.63\cdot 10^{-34}}{\sqrt{2(6.4\cdot 10^{-13})(1.67\cdot 10^{-27})}}=14.3\cdot 10^{-15} m = 14.3 fm

b)

In this case, the electron has kinetic energy of 40 GeV, while the rest mass of an electron is

m_0 = 0.511 MeV

Since 40 GeV >> 0.511 MeV, the electron is ultra-relativistic: so we can rewrite its energy as

E = pc

The equation (1) can also be rewritten as

\lambda = \frac{hc}{pc}

where c is the speed of light. The quantity at the denominator is the energy, so

\lambda=\frac{hc}{E}

where:

E=40 GeV = 40\cdot 10^9 eV \cdot (1.6\cdot 10^{-19})=6.4\cdot 10^{-9} J is the energy of the electron

And substituting, we find:

\lambda=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{6.4\cdot 10^{-9}}=3.1 \cdot 10^{-17} m = 0.031 fm

Learn more about de Broglie wavelength:

brainly.com/question/7047430

#LearnwithBrainly

4 0
3 years ago
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