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otez555 [7]
2 years ago
14

Uses of hydrometer in points​

Physics
1 answer:
Arisa [49]2 years ago
7 0

Answer:

A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water

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Help fast plssssssssssss
lyudmila [28]

Answer:

star

Explanation:

because that is what our sun is.

5 0
2 years ago
In the diagram, q1=+6.25 * 10^ -8 C. What is the potential difference when you go from point A to point B? Include the correct s
Nimfa-mama [501]

Answer:

Moving a unit "positive" test charge from A to B will result in a reduction in potential

V = K Q / R      potential at a point

V2 - V1 = K Q (1 / .4 - 1 / .15) = = k Q (.15 - .4) / .06 = -4.17 K Q

V2 - V1 = -4.17 * 9 & 10E9 * 6.25 E-8

V2 - V1 = -4.17 * 562.5 J/C

V = - 2346 Volts

7 0
2 years ago
What is the charge on a
Marrrta [24]

Answer:

positive

Explanation:

The electrons revolves around the nucleus and they are negatively charged. The nucleus consists of protons and neutrons. The neurons have no charge but the protons are positively charged.

7 0
3 years ago
Deceleration ALWAYS means slowing down while negative acceleration does not always have to be slowing down
alexgriva [62]
A little confused by the wording of the problem, but it is true that an object can have a negative acceleration and be speeding up in the negative direction… so I’d go with True
4 0
2 years ago
a sprinter running a 100m dash leaves the starting block and accelerates to a maximum velocity of 11m/s at 6s into the race. the
mihalych1998 [28]

Answer:

Part(a): The average acceleration is 1.83~m~s^{-2} during the first 6s.

Part(b): The average acceleration from 6s to 8s is zero.

Explanation:

Part(a):

The average acceleration is defined as the rate at which velocity is changing with respect to time. So if 'v_{i}', 'v_{f}' and 'a_{av}' represents the initial velocity, final velocity, and average acceleration of a particle, then mathematically

a_{av} = \dfrac{v_{f} - v_{i}}{t}

where 't' is the time taken by the particle to achieve the velocity 'v_{f}' starting from initial velocity 'v_{i}'

Given in the problem, v_{i} = 0, v_{f} = 11~m~s^{-1}~and~t = 6~s.

So the average acceleration(a_{av}) during the first 6 s will be

a_{av} = \dfrac{11 - 0}{6}~m~s^{-2} = 1.83~m~s^{2}

Part(b):

During the time between 6 s to 8 s, as mentioned in the problem, the sprinter maintains the constant velocity. So the average acceleration during this time interval will be zero.

7 0
3 years ago
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