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neonofarm [45]
3 years ago
5

A wire is stretched between two posts. Another wire is stretched between two posts that are three times as far apart. The tensio

n in the wires is the same, and they have the same mass. A transverse wave travels on the shorter wire with a speed of 170 m/s. What would be the speed of the wave on the longer wire?
Physics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

v_1 =294.45\ m/s

Explanation:

given,

Length of shorter wire is L and mass m and tension T

v_1 = \sqrt{\dfrac{TL}{m}}

if all other dimension is same but length is increased by 3 times

v_1 = \sqrt{\dfrac{T(3 L)}{m}}

v_1 =\sqrt{3} \sqrt{\dfrac{T L}{m}}

v_1 =\sqrt{3}\ v_1

v_1 =\sqrt{3}\ \times 170

v_1 =1.732\ \times 170

v_1 =294.45\ m/s

the speed of the wave on the longer wire v_1 =294.45\ m/s

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With that in mind, apply the right-hand rule to find the direction of the force on the coil in each of the two possibilities.

Assume that when viewed from above, the current is flowing towards the top-right corner of the picture. Consider the wire near the top-right corner of this coil (as viewed above on this picture.) The current will be going into the picture into the magnetic field. By the right-hand rule, the current on the wire near that point should be pointing towards the bottom of this picture. (Point fingers on the right hand in the direction of the current I. Rotate the right hand such that when curling the fingers, they point in the direction of the magnetic field B. The direction of the right thumb should now point in the direction of the force on the wire F.)

Based on the same assumption, the current in the wires near the bottom left corner of this coil will be pointing out of the picture. By the right hand rule, the magnetic force on the coil in that region should be pointing towards the top of this picture. Combing these two forces, the coil would indeed be rotating around the center of this picture in the direction shown in the diagram.

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