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3 years ago

What provides the energy to set the water cycle in motion?

Chemistry

1 answer:

LekaFEV [45]3 years ago

4 0

The water cycle is driven by the energy from the sun.

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When adding the measurements 42.1014 g + 190.5 g, the answer has ___ significant figures.

andrezito [222]

Answer: The answer has 7 significant figures

Explanation:

The addition of 190.5 and 42.1014 will give 232.6014. Counting the digits will give 7 significant figures.

4 0

3 years ago

What is Ka for H3PO4(aq) ⇌ H+(aq) + H2PO4-(aq) a. Ka = (H3PO4)/(h+)(H2PO4-) B. Ka = (H3PO4)(H+)(H2PO4-) C. Ka = (H3PO4)/(H+)(H2P

Eva8 [605]

Answer:

The answer is option d.

Ka = (H+)(H2PO4-)/(H3PO4)

Hope this helps.

3 0

3 years ago

A sample of oxygen gas was collected via water displacement. since the oxygen was collected via water displacement, the sample i

mylen [45]

The sample of oxygen gas was collected through water displacement. So, the gas collected will be a mixture of oxygen and water vapor.

Given that the total pressure of the mixture of gases containing oxygen and water vapor = 749 Torr

Vapor pressure of pure water at $26.4^{0}C$ =25.81mmHg

= $25.81 mmHg*\frac{1 Torr}{1 mmHg} =25.81 Torr$

According to Dalton's law of partial pressures,

Total pressure = Partial pressure of Oxygen gas + Partial pressure of water

749 Torr = Partial pressure of Oxygen gas + 25.81 Torr

Partial pressure of Oxygen gas = 749 Torr - 25.81 Torr = 723.19 Torr

Therefore the partial pressure of Oxygen gas in the mixture collected will be 723.19 Torr

6 0

3 years ago

How is petrol separated from the mixture of hydrocarbons in crude oil?

S_A_V [24]

By doing fractional distillation

5 0

3 years ago

Read 2 more answers

What is the empirical formula of an oxide of nitrogen containing 63.61% by mass of nitrogen and 36.69% by mass of oxygen?

katen-ka-za [31]

Answer:

D. N₂O

Explanation:

Let's assume we have 100 g of the compound. That means it consists of 63.61 grams of nitrogen and 36.69 grams of oxygen.

Converting masses to moles:

63.61 g N × (1 mol N / 14.01 g N) = 4.540 mol N

36.69 g O × (1 mol O / 16.00 g O) = 2.293 mol O

Normalize by dividing by the smallest:

4.540 / 2.293 = 1.980 mol N

2.293 / 2.293 = 1.000 mol O

So there is approximately twice as many N atoms as O atoms. The empirical formula is therefore N₂O.

8 0

3 years ago