How many protons and electrons are present in the mg2+ ion?
1 answer:
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Answer:1) Volume of required is 55.98 mL.
2) 0.62577 grams of is produced.
Explanation:
1) Molarity of
Volume of
Molarity of
Volume of
According to reaction, 1 mole of reacts with 3 mole of
, then, 0.0041985 moles of
will react with:
moles of
that is 0.0125955 moles.
Volume of required is 55.98 mL.
2)
Number of moles of
According to reaction, 3 moles of gives 1 mole of
, then 0.004485 moles of
will give:
moles of
that is 0.001495 moles.
Mass of =
Moles of × Molar Mass of
= 0.001495 moles × 418.58 g/mol = 0.62577 g
0.62577 grams of is produced.
Answer:
Explanation:
<u>1. Convert Molecules to Moles</u>
First, we must convert molecules to moles using Avogadro's Number: 6.022*10²³. This tells us the number of particles in 1 mole of a substance. In this case, the particles are molecules of sodium hydroxide.
Multiply by the given number of molecules.
Flip the fraction so the molecules cancel out.
<u>2. Convert Moles to Grams</u>
Next, we convert moles to grams using the molar mass.
We must calculate the molar mass using the values on the Periodic Table. Look up each individual element.
- Na: 22.9897693 g/mol
- O: 15.999 g/mol
- H: 1.008 g/mol
Since the formula has no subscripts, we can simply add the molar masses.
- NaOH: 22.9897693+15.999+1.008=39.9967693 g/mol
Use this as a ratio.
Multiply by the number of moles we calculated.
The moles of sodium hydroxide cancel.
The original measurement of molecules has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 0 tells us to leave the 7 in the hundredth place.
1.20*10²² molecules of sodium hydroxide is approximately 0.797 grams.