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Gnesinka [82]
4 years ago
5

How many protons and electrons are present in the mg2+ ion?

Chemistry
1 answer:
Lorico [155]4 years ago
7 0
There are 12<span> protons and </span>10<span> electrons in a </span><span>Mg<span>2+</span></span><span> ion, the normal amount of neutrons is </span>12<span>.</span>
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n the laboratory, two forms of sodium phosphate will be available (the monobasic monohydrate NaH2PO4·H2O, F.W. = 137.99 g/mol, a
const2013 [10]

Answer:

The compound you will use is the Dibasic phosphate

Explanation:

Simple phosphate buffer is used ubiquitously in biological experiments, as it can be adapted to a variety of pH levels, including isotonic. This wide range is due to phosphoric acid having 3 dissociation constants, (known in chemistry as a triprotic acid) allowing for formulation of buffers near each of the pH levels of 2.15, 6.86, or 12.32. Phosphate buffer is highly water soluble and has a high buffering capacity,

In this case the most efficient way is to disolve the dibasic compound which in the reaction with the water will form the monobasic phosphate.

To make the buffer you have to prepare the amount of distillate water needed, disolve the dibasic phospate, and then adjust with HCl or NaOH depending on the pH needed.

6 0
3 years ago
What is the definition of electron orbital?
Vlada [557]
A function describing the location and wave-like behavior of an electron in an atom.
8 0
2 years ago
Read 2 more answers
In a boys hostel, 1206 eggs were bought for breakfast for the students. How many moles of eggs does this represent?
Evgen [1.6K]

Answer:

6.022×1023

Here, it has been asked how many eggs are in one mole of eggs. The eggs represent the unit which can be atom, ion or molecule. So by the definition of mole, 6.022×1023number of eggs are present in one mole of eggs.

8 0
2 years ago
How many grams of FeCl 3 are in 250. mL of a 0.100 M solution?
Naddika [18.5K]

Answer:

The correct answer is option B

Explanation:

$Molarity=\frac{Weight}{Molecular \,weight} \frac{1000}{V(in \, ml)}

Given values,

Molarity of $FeCl_3=0.100M$

Volume of solution, $V=250ml$

Molecular weight of $FeCl_3=162.2$

Substituting this values in Molarity formula, we get

$0.1=\frac{weight}{162.2} \times\frac{1000}{250} $\\$\Rightarrow 16.22=weight\times4$\\$\Rightarrow weight=\frac{16.22}{4} $\\$\therefore weight=4.06g$

5 0
4 years ago
Can someone please help
miskamm [114]

Answer:

b

Explanation:

6 0
3 years ago
Read 2 more answers
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