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aleksklad [387]
2 years ago
14

What current is required in the windings of a long solenoid that has 1580 turns uniformly distributed over a length of 0.44 m in

order to produce a magnetic field of magnitude 0.000394 T at the center of the solenoid
Physics
1 answer:
Dominik [7]2 years ago
6 0

The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.

<h3>Magnetic field at the center of a solenoid</h3>

The magnetic field at the center of a solenoid is given by the following formula,

B = μ₀nI

where;

  • μ₀ is permeability of free space
  • n is number of turns
  • I is current in the solenoid
<h3>Current in the solenoid</h3>

I = B/μ₀n

I = (0.00394) / (4π x 10⁻⁷ x 1580)

I = 1.98 A

Thus, the current required in the windings of the given long solenoid is 1.98 A.

Learn more about current in solenoid here: brainly.com/question/17086348

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Correction

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