What current is required in the windings of a long solenoid that has 1580 turns uniformly distributed over a length of 0.44 m in
order to produce a magnetic field of magnitude 0.000394 T at the center of the solenoid
1 answer:
The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.
<h3>
Magnetic field at the center of a solenoid</h3>
The magnetic field at the center of a solenoid is given by the following formula,
B = μ₀nI
where;
- μ₀ is permeability of free space
- n is number of turns
- I is current in the solenoid
<h3>Current in the solenoid</h3>
I = B/μ₀n
I = (0.00394) / (4π x 10⁻⁷ x 1580)
I = 1.98 A
Thus, the current required in the windings of the given long solenoid is 1.98 A.
Learn more about current in solenoid here: brainly.com/question/17086348
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