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aleksklad [387]
2 years ago
14

What current is required in the windings of a long solenoid that has 1580 turns uniformly distributed over a length of 0.44 m in

order to produce a magnetic field of magnitude 0.000394 T at the center of the solenoid
Physics
1 answer:
Dominik [7]2 years ago
6 0

The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.

<h3>Magnetic field at the center of a solenoid</h3>

The magnetic field at the center of a solenoid is given by the following formula,

B = μ₀nI

where;

  • μ₀ is permeability of free space
  • n is number of turns
  • I is current in the solenoid
<h3>Current in the solenoid</h3>

I = B/μ₀n

I = (0.00394) / (4π x 10⁻⁷ x 1580)

I = 1.98 A

Thus, the current required in the windings of the given long solenoid is 1.98 A.

Learn more about current in solenoid here: brainly.com/question/17086348

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A galaxy spectrum has a redshift of 70,000 km per second. If the Hubble constant is 70 km per second per Mpc (megaparsec), how f
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brainly.com/question/18484687

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A wave is traveling at a speed of 15 m/s and it's wavelength is 5 m. Calculate the waves frequency
Anvisha [2.4K]

Answer:

The frequency of this wave is 3\; \rm Hz.

Explanation:

The frequency f of a wave is the number of wavelengths that this wave covers in unit time (typically a second.)

The wave in this question travels at v = 15\; \rm m \cdot s^{-1}. In other words, this wave covers 15\; \rm m in unit time (a second.) How many wavelengths \lambda would that 15\; \rm m\; correspond to?

The question states that the wavelength of this wave is \lambda = 5\; \rm m. Therefore, there would be 15 / 5 = 3 wavelengths in the 15\; \rm m span that this wave covered in the unit time of one second (1\; \rm s.) Hence, the frequency of this wave would be 3\; \rm s^{-1} (three per second,) which is equivalent to 3\; \rm Hz (three Hertzs.)

In general, the frequency f of a wave with speed v and wavelength \lambda would be:

\displaystyle f = \frac{v}{\lambda}.

For the wave in this question:

\begin{aligned}f &= \frac{v}{\lambda} \\ &= \frac{15\; \rm m \cdot s^{-1}}{3\; \rm s} = 3\; \rm s^{-1} = 3\; \rm Hz\end{aligned}.

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Answer: .8

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