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aleksklad [387]
2 years ago
14

What current is required in the windings of a long solenoid that has 1580 turns uniformly distributed over a length of 0.44 m in

order to produce a magnetic field of magnitude 0.000394 T at the center of the solenoid
Physics
1 answer:
Dominik [7]2 years ago
6 0

The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.

<h3>Magnetic field at the center of a solenoid</h3>

The magnetic field at the center of a solenoid is given by the following formula,

B = μ₀nI

where;

  • μ₀ is permeability of free space
  • n is number of turns
  • I is current in the solenoid
<h3>Current in the solenoid</h3>

I = B/μ₀n

I = (0.00394) / (4π x 10⁻⁷ x 1580)

I = 1.98 A

Thus, the current required in the windings of the given long solenoid is 1.98 A.

Learn more about current in solenoid here: brainly.com/question/17086348

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all objects near the earths surface-regardless of size and weight have the same force of gravity acting on them. is it true or f
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False: the force of gravity acting on different objects is different and depends on their mass

Explanation:

The answer is false.

The force of gravity acting on an object (also known as weight) near the Earth's surface is given by:

F=mg

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

We see from the formula that the force of gravity acting on an object depends on the mass: the larger the mass of the object, the stronger the gravitational force acting on it, and the smaller the mass, the weaker the force of gravity.

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5 0
3 years ago
A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift i
WINSTONCH [101]

Answer:

Total work done = = 29811.60 J

Explanation:

Since the person is being moved upward, the person’s potential and kinetic energy are increasing.

To determine the increase in potential energy, the following equation is used;

∆ PE = m * g * ∆ h

m = 78.0 Kg, g = 9.8 m/s, ∆ h = 13.0 m

∆ PE = 78.0 * 9.8 * 13.0 = 9937.20 J

Increase in kinetic energy is given by the following equation;

∆ KE = ½ * m * (vf² – vi²)

vf = 3.4, vi = 0

∆ KE = ½ * 78.0 * 3.4² = 450.84 J

Total work = 9937.20 + 450.84 = 10388.04 J

(b) He is then lifted at the constant speed of 3.40 m/s

Velocity is constant, therefore, there is no increase in kinetic energy. The only work done is the increase of potential energy

∆ PE = 78.0 * 9.8 * 13.0

∆ PE = 9937.20 J

(c) He is then decelerated to zero speed.

Since his velocity decreased from 3.40 m/s to 0 m/s, his kinetic energy decreased.

∆ KE = ½ * 78.0 * (0² - 3.4²)

∆ KE = - 450.84 J

∆ PE = 78.0 * 9.8 * 13.0 = 9937.20 J

Total work = 9937.20 - 450.84 = 9486.36 J

Sum of works = 10388.04 + 9937.20 + 9486.36 = 29811.60 J

8 0
2 years ago
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