What current is required in the windings of a long solenoid that has 1580 turns uniformly distributed over a length of 0.44 m in
 order to produce a magnetic field of magnitude 0.000394 T at the center of the solenoid
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.
<h3>
Magnetic field at the center of a solenoid</h3>
The magnetic field at the center of a solenoid is given by the following formula,
B = μ₀nI
where;
- μ₀ is permeability of free space 
- n is number of turns
- I is current in the solenoid
<h3>Current in the solenoid</h3>
I = B/μ₀n
I = (0.00394) / (4π x 10⁻⁷ x 1580)
I = 1.98 A
Thus, the current required in the windings of the given long solenoid is 1.98 A.
Learn more about current in solenoid here: brainly.com/question/17086348
 
                                
             
         	    You might be interested in
    
        
        
Answer: Hello, The opposite of rebel is  supporter, adherent.
Explanation:
 
        
             
        
        
        
Wood isn’t a medium. Pls give brainliest
        
             
        
        
        
The ratio of the turns to the voltage should be equal
i.e: 200/120 = t/12
so the secondary coil should have 20 turns
        
             
        
        
        
Answer:
its not moving at a constant velocity because it is slowing down
Explanation:
 
        
                    
             
        
        
        
2^4/2^7 = 16/128 = 0.125
(1/2)^3= 0.125
1/8= 0.125
a and f are equivalent