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3 years ago

This is a compound made from a group of covalently bonded atoms.

Physics

2 answers:

Effectus [21]3 years ago

6 0

molecule hope this helps

ra1l [238]3 years ago

3 0

The answer is molecule

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A 2 kg block is on a horizontal surface. A horizontal force is applied by a person to the block to pull it on the surface with a

Agata [3.3K]

Answer:

work done = 500 J

option e is correct

Explanation:

given data

mass = 2 kg

acceleration = 2 m/s

coefficient of kinetic friction = 0.3

block D = 50 m

to find out

work

solution

we know that work done is

work done = f × d ...........1

here f is force and d is block i.e 50 m

so here

force , f - k mg =ma

f = 2 ( 2 + 0.3 ×10 )

f = 10 N

so from equation 1

work done = f × d

work done = 10 × 50

work done = 500 J

option e is correct

3 0

3 years ago

Explain briefly why the intensity reflected off the back surface of the film (i.e., the right surface, where there is a liquid-t

Katarina [22]

Explanation:

Taking the incident light to be traveling in the + x-direction so that it is at normal incidence to the left side of the film(referred to as the "Front side"). This means the beam transmitted into the liquid is essentially as strong as the incident beam.

Almost all the light that is reflected off the back surface will get through the front surface. (But only 2.78% gets re-reflected off the the front surface back to the right) this means that there are two beams reflected to the - x-direction, one from the front surface and one from the back, and these beams are of almost equal intensity.

Hope this is helpful. Thanks

7 0

3 years ago

Suppose that a merry-go-round, which can be approximated as a disk, has no one on it, but it is rotating about a central vertica

seropon [69]

Answer:

0.1 rev/s

Explanation:

M = mass of the merry go round = 200 kg

R = radius of merry go round = 6 m

$I_{o}$ = Moment of inertia of merry go round = (0.5) MR² = (0.5) (200) (6)² = 3600 kgm²

m = mass of the man = 100 kg

$I_{f}$ = Moment of inertia of merry go round when man sits on it at the edge = (0.5) MR² + mR² = (0.5) (200) (6)² + (100) (6)² = 7200 kgm²

$w_{o}$ = initial Angular speed of merry-go-round before man sit = 0.2 rev/s

$w_{f}$ = Angular speed of merry-go-round after man sit = ?

Using conservation of angular momentum

$I_{o}$ $w_{o}$ = $I_{f}$ $w_{f}$

(3600) (0.2) = (7200) $w_{f}$

$w_{f}$ = 0.1 rev/s

4 0

3 years ago

What are three types of muscle fibers?

Arisa [49]

The Answer is C.

Type I - Slow Twitch

Type II - Fast Twitch Oxidative

Type III - Fast twitch Glycolytic

7 0

3 years ago

Read 2 more answers

What is universal constant (G)

ahrayia [7]

☄ Universal Gravitational Constant(G)

Gravitational constant is a constant of proportionality when F(Gravitational force) is proportional to product of masses and inversely proportional to the distance between them.

It can be defined as:- Universal gravitational constant is the magnitude of the force between a pair of 1 kg masses that are kept 1 metre apart.
The SI unit of G is N m²/kg² and the CGS unit of G is Dyne cm² / g².

The value of G (universal gravitational constant) was found out by the scientist Henry Cavendish by using the sensitive torsion balance $.$

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8 0

3 years ago

Read 2 more answers