Answer:
190×0.5=95N
Explanation:
The spring constant is 190 N/m . Therefore the force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m is 95 N
Height of the rocket will be <span>h(t)=−<span>12</span>g<span>t2</span>+<span>v0</span>tsinθ+<span>h0</span></span> where
<span>g=9.8<span> m/s2</span></span>
<span><span>v0</span>=86 m/s</span>
<span><span>h0</span>=0 m</span>
<span>θ= angle formed with the vertical
</span>
That's a parabola. You'll solve that for <span>h(<span>tf</span>)=0</span> to find the time of flight.
The horizontal component of the rocket's velocity will be <span><span>vx</span>=<span>v0</span>cosθ</span>. You know that <span>x=<span>vx</span><span>tf</span>=104 m</span> where <span>tf</span> is the time of flight. You can use that relationship to write an expression for <span>tf</span> in terms of <span>v0</span> and θ. Substitute that into the first equation and solve for θ.
Once you've got the parabola figured out, you can easily find the maximum height by finding the vertex, and you've already found the duration of the flight.
<span>Here's your explanation:
R = k / d^2 (k is a constant, unknown)
</span><span>d1 = 0.01 and R1 = 0.306
d2 = 0.0299 R2 = ?
</span>
<span>Use the equation in line 1 for both case and divide and k will go away and you can find R2</span>
To get the velocity you need to know the displacement and the time.
I hope that helps!
