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IRISSAK [1]
2 years ago
11

Find the probability of each event

Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

Around 77%

Step-by-step explanation:

10/13 = 0.769

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Answer:

m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles m\angle CDB=m\angle CDA=90°

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha

From ΔCBD,

m\angle CBD is same as m\angle B.

So, m\angle CBD=90-\alpha

m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha

Now, from ΔCAD,

m\angle CAD is same as m\angle A

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m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha

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m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

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Answer:

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