All categories

1 year ago

1. Potential energy and a roller coaster. A 1000-kg roller coaster car moves from point A to B then C.

1 answer:

8 0

Answer:(a) With our choice for the zero level for potential energy of the car-Earth system when the car is at point B ,

When the car is at point A, the potential energy of the car-Earth system is given by

=mgy

where y is the vertical height above zero level. With 135ft=41.1m, this height is found as:

y=(41.1m)sin40.0

=26.4m

Thus,

=(1000kg)(9.80m/s

)(26.4m)=2.59∗10

The change in potential energy of the car-Earth system as the car moves from A to B is

−U

=0−2.59∗10

J=−2.59∗10

(b) With our choice of the zero configuration for the potential energy of the car-Earth system when the car is at point A, we have U

=0. The potential energy of the system when the car is at point B is given by U

=mgy, where y is the vertical distance of point B below point A. In part (a), we found the magnitude of this distance to be 26.5m. Because this distance is now below the zero reference level, it is a negative number.

Thus,

You might be interested in

The force diagram shown here describes the forces that external objects (the surface andEarth) exert on a woman (in this scenari

sveticcg [70]

The three different motions are;

The upward motion of the woman is constant
The downward motion of the woman is also constant
The horizontal motion of the woman is zero.

<h3>What is force diagram?</h3>

Force diagram is a pictorial or graphical illustration of different forces acting on object.

In this given question, there two forces acting on the woman as depicted in the force diagram.

The first force is surface force (Fs)
The second force is force of Earth (FE)

In the given force diagram, the woman is in equilibrium, this implies that the surface force and the Earth force are equal.

The three different types of motion of the woman that are consistent with the force diagram include the following;

The upward motion of the woman is constant
The downward motion of the woman is also constant
The horizontal motion of the woman is zero since there is no horizontal force on the woman.

Learn more about force diagram here: brainly.com/question/3624253

#SPJ1

4 0

8 months ago

PLEASE HELP!!!!!!

Helga [31]

Hey there,

Density = Mass/Valume

D= 3.1/0.35

D= 8.86 g/cm3

3 0

3 years ago

Read 2 more answers

In which direction is the magnetic force acting on the charge? into the screen out of the screen up down

Harrizon [31]

The direction in which the magnetic force is acting on the charge is upwards.

<h3>What is Magnetic force?</h3>

This is the attraction and repulsion which usually occurs during the motion of electrically charged particles.

In the magnetic field, the charge is moving to the left. Therefore the direction the magnetic force is acting on the charge is upwards which is gotten via right hand rule.

Read more about Magnetic force here brainly.com/question/25932320

#SPJ1

4 0

1 year ago

In 2 minutes, a ski lift raises four skiers at a constant speed to a height of 123 m. The average mass of each skier is 71 kg. W

serious [3.7K]

Answer:

The average power provided by the tension in the cable pulling the lift is = 714 W

Explanation:

Given data

Mass = 71 kg

Change in height = 123 m

When the lift moves in upward direction then in that case kinetic energy is constant & only potential energy changes.

Change in potential energy Δ PE = m g ( $h_f - h _ i$ )

Δ PE = 71 × 9.81 × 123

Δ PE = 85670.73 J

Time = 2 min = 120 sec

So average power is given by

$P_{avg} = \frac{Change \ in \ potential \ energy}{Time}$

$P_{avg} = \frac{85670.73}{120}$

$P_{avg} = 714 \ W$

Therefore the average power provided by the tension in the cable pulling the lift is = 714 W

7 0

2 years ago

A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much

7nadin3 [17]

Answer:

P₀ = 5.76 x 10⁻² MW

Explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

$\eta = \dfrac{P_0}{P}$

where P is the power produced in the power plant

P₀ is the power output of the power plant

$\eta = \dfrac{P_0}{P}$

$0.32 = \dfrac{P_0}{0.18}$

P₀ = 0.18 x 0.32

P₀ = 0.0576 MW

P₀ = 5.76 x 10⁻² MW

Power plant output is equal to P₀ = 5.76 x 10⁻² MW

8 0

3 years ago