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Luba_88 [7]
3 years ago
7

/

Physics
2 answers:
Mumz [18]3 years ago
4 0
No se ha da han dicho nada más de lo dicho y han ido de vuelta y han dicho nada más de que se pueda hacer el favor del niño
kiruha [24]3 years ago
3 0

Answer:

The amount of sunlight

Explanation:

The sun is independent but the plants are dependent on the sunlight

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A ray of light is moving from a material having a high indexof refraction into a material with a lower index of refraction.
luda_lava [24]

(a) Away from the normal

We can find the direction of bending of the ray of light by using Snell's equation:

n_1 sin \theta_1 = n_2 sin \theta_2

where we have:

n1, n2: index of refraction of the first and second medium

\theta_1, \theta_2; angle that the incident and the refracted ray form with the normal to the surface

Here, the light ray moves from a material with high index of refraction to a material with lower index, so we have

n_1 > n_2

Re-arranging Snell's law we find

sin \theta_2 = \frac{n_1}{n_2} sin \theta_1

since we have

\frac{n_1}{n_2}>1

this implies

sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 is the wavelength of the light in a vacuum

n is the refractive index

The equation can be rewritten as

\lambda_0 = \lambda_1 n_1 = \lambda_2 n_2

and again it can be rewritten as

\lambda_2 = \frac{n_1}{n_2} \lambda_1

where

\lambda_1 = 600 nm\\\frac{n_1}{n_2}>1

Therefore, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency remains the same

Wavelength and speed of a light ray depend on the medium in which the wave is travelling through, however the frequency does not depend on that, so it remains the same in the two mediums.

8 0
3 years ago
Canada geese migrate essentially along a north–south direction for well over a thousand kilo-meters in some cases, traveling at
kotykmax [81]

Answer:

a) 66.4 relative to the west in the south-west direction

b) 5.455 hours

Explanation:

a)If the wind is blowing east-ward at a speed of 40km/h, then the west component of the geese velocity must be 40km/h in order to counter balance it. Geese should be flying south-west at an angle of

cos(\alpha) = 40 / 100 = 0.4

\alpha = cos^{-1}(0.4) = 1.16 rad = 180\frac{1.16}{\pi} = 66.4^0 relative to the West

b) The south-component of the geese velocity is

100sin(\alpha) = 100sin(66.4^0) = 91.65 km/h

The time it would take for the geese to cover 500km at this rate is

t = 500 / 91.65 = 5.455 hours

7 0
3 years ago
In the Olympic shot-put event, an athlete throws the shot with an initial speed of 12.0 m/s at a 40.0 ∘ angle from the horizonta
Gre4nikov [31]

Answer:

Explanation:

given,

initial speed of the shot = 12.0 m/s

angle = 40°

height at which shot leaves her hand = 1.80 m

v_x = 12 cos 40° = 9.19 m/s

v_y = 12 sin 40° = 7.71 m/s

time to reach maximum height =

     = \dfrac{v_y}{g}

     = \dfrac{7.71}{9.8}

     = 0.787 s

h = v_y t + \dfrac{1}{2}gt^2

h = 7.71 × 0.787 - 0.5 × 9.81 × 0.787²

h = 3.03 m

the maximum height attain = 3.03 + 1.8 = 4.83 m

now free fall from the maximum height

h =\dfrac{1}{2}gt^2

4.83 = \dfrac{1}{2}\times 9.8 \times t^2

t = 0.9928 s

total time = 0.9928 + 0.787 = 1.7798 s

range =

d = vₓ t

d = 16.36 m

8 0
4 years ago
A force produces an acceleration of 5 ms
Dmitrij [34]

F = m • a (I. Newton)

F = (4 kg) x (5 m/s^2)

F = 20 Newtons

8 0
3 years ago
A brick is dropped from rest from a height of 4.9 m. how long does it take the brick to reach the ground?
Igoryamba

We know the equation of motion , s =ut+\frac{1}{2} at^2, where s is the displacement, u is the initial velocity, a is the acceleration and t is the time taken.

In this case a brick is dropped from rest from a height of 4.9 m, so displacement, s = 4.9 m

Since the brick is dropped from rest, u = 0 m/s

Acceleration on brick = acceleration due to gravity = 9.81 m/s^2

Substituting

   4.9 = 0*t+\frac{1}{2} *9.81*t^2\\ \\ 4.9 = 4.9t^2\\ \\ t^2=1\\ \\ t =1 second

So the brick will reach ground after 1 second.


8 0
3 years ago
Read 2 more answers
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