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dsp73
2 years ago
11

When different elements react, their atoms join with other atoms.

Chemistry
1 answer:
FinnZ [79.3K]2 years ago
8 0

Answer:

compound is formed .............

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What is the hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4.
Maksim231197 [3]

The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7.

pH= -log[H+] - (i)

10^-3=H2So4

H+= 2×10-3

here ,

h2so4 ——— 2[H+] + so4^2-

thus [H+]= 2*10^(-3) because hydrogen ion has two moles

pH= -log[H+]

pH= -log(2×10^-3)

pH= 3-log2

pH= 3-log2pH= 2.7

The pH is 2.7

<h3>What is pH?</h3>

PH is the degree of alkalinity and acidicity in a solution.

Therefore, The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7

Learn more about pH from the link below.

https://brainly.in/question/9937410

4 0
2 years ago
How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?
Vladimir [108]
Note that it says oxygen "gas"
So you need the atomic mass of oxygen gas

Look at your periodic table, you'll see 15.9994 under oxygen
Oxygen gas has a formula of O2 therefore,
(15.9994) times 2= Oxygen gas atomic mass=31.9988

Mol= Mass/Atomic Mass
=62.3 g/ 31.9988 g/mol = 1.95 mol

now look at the ratio of C2H6 and O2, notice there is an invisible number beside each of them, at that "invisible number" is =1

1 C2H6 + 1 O2 -> products

this means that for 1 mol of C2H6, 1 mol of O2 has to react with it

Thus as we have 1.95 moles of O2, we need 1.95 moles of C2H6
5 0
3 years ago
Does sound travel faster in a warm room or a cold room? Explain your answer.
RUDIKE [14]

Answer:

Explanation:

Sound travels outwards from the source in all directions. So there you have it sound does travel faster in warm air BUT it may appear to travel farther in cold air. This is how that works……if the air close to the ground is colder than the air above it then sound waves travelling upwards will be bent downwards.

4 0
3 years ago
Read 2 more answers
Evaluate the exponential expression (−2)6.
Olegator [25]

A general exponential expression is something like:

A^n

This means that we need to multiply the number A by itself n times.

Using that we will get (-2)^6 = 64

With that definition, we can rewrite:

(-2)^6 = (-2)*(-2)*(-2)*(-2)*(-2)*(-2)

So we just need to solve the above expression.

Also, remember the rule of signs:

(-)*(-) = (+)

We will get:

(-2)*(-2)*(-2)*(-2)*(-2)*(-2) =  [(-2)*(-2)]*[(-2)*(-2)]*[(-2)*(-2)]

                                        =  4*4*4 = 16*4 = 64

Then we got:

(-2)^6 = 64

If you want to learn more, you can read:

brainly.com/question/17172630

6 0
2 years ago
A sample of argon has a volume of 1.2 L at STP. If the temperature is increased to 21 c and the pressure is lowered to 0.80 atm,
Nuetrik [128]

Answer:

The new volume is 1.62 L

Explanation:

Boyle's law says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." It is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. So this law indicates that the quotient between pressure and temperature is constant.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law.

\frac{P*V}{T}=k

Having an initial state 1 and a final state 2 it is possible to say that:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Standard temperature and pressure (STP) indicate pressure conditions P = 1 atm and temperature T = 0 ° C = 273 ° K. Then:

  • P1= 1 atm
  • V1= 1.2 L
  • T1= 273 °K
  • P2= 0.80 atm
  • V2= ?
  • T2= 21°C= 294 °K

Replacing:

\frac{1 atm* 1.2 L}{273K} =\frac{0.8 atm*V2}{294K}

Solving:

V2=\frac{1 atm*1.2 L}{273 K} *\frac{294 K}{0.8 atm}

V2= 1.62 L

<u><em>The new volume is 1.62 L</em></u>

<u><em></em></u>

8 0
2 years ago
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