Question

12.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?

Answer 1

Answer: 7.693 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=0.63atm\\V_1=12.70L\\P_2=105kPa=1.04atm(1kPa=0.009atm)\\V_2=?$

Putting values in above equation, we get:

$0.63\times 12.70mL=1.04\times V_2\\\\V_2=7.693L$

Thus new volume of the gas is 7.693 L

Answer 2

Answer:

7.72 L

Explanation:

The volume of the gas at 105 kPa would be 7.72 L.

First, let us convert the pressures into the same unit.

1 kPa = 0.00986923 atm

105 kPa = 105 x 0.00986923 = 1.0363 atm

From Boyle's law, the volume of gas is inversely proportional to the pressure of the gas. Mathematically;

$P_1V_1 = P_2V_2$

In this case, $P_1$ = 0.63, $V_1$ = 12.70, $P_2$ = 1.0363, $V_2$ = ?

Make $V_2$ the subject of the formula;

$V_2 = \frac{P_1V_1}{P_2}$

Hence,

$V_2$ = 0.63 x 12.70/1.0363

     = 7.72 L