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elena-s [515]
3 years ago
7

How do structures stand up under a load

Chemistry
1 answer:
shusha [124]3 years ago
8 0

Answer:

The force then channels down through the walls to the floor. The force of the walls pushing down on the floor is exactly balanced by an equal force when the floor pushes up on the wall. ... The main, structural walls are called load-bearing walls and they're usually built from solid brick or stone.

Explanation:

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Which hold more heat for longer period of time ? <br><br> A. Air <br> B. Water
Mandarinka [93]

Answer:

water

Explanation:

The heat capacity of a material, along with its total mass and its temperature, tell us how much thermal energy is stored in a material. ... <u>The result is that the temperature of the water cube is much more stable than the air — the water changes much more slowly; it holds onto its temperature longer.</u>

8 0
2 years ago
Read 2 more answers
If 5 grams of hydrogen reacted with 40 games of oxygen to form water, how much of water would be formed?
GREYUIT [131]
2H₂ + O₂ = 2H₂O

n(H₂)=m(H₂)/M(H₂)
n(H₂)=5g/2.0g/mol=2.5 mol

n(O₂)=m(O₂)/M(O₂)
n(O₂)=40g/32.0g/mol=1.25 mol

H₂ : O₂ = 2 : 1

2.5 : 1.25 = 2 : 1

n(H₂O)=n(H₂)=2n(O₂)=2.5 mol

m(H₂O)=n(H₂O)M(H₂O)

m(H₂O)=2.5mol*18.0g/mol=45.0 g
3 0
2 years ago
Write down all the food chains that start with the blackberry and end with the hawk.
Roman55 [17]
Blackberry - rabbit - snake - owl - hawk<span>
</span>
6 0
3 years ago
The empirical formula is:
stepan [7]

Answer:

option c the relative number of atoms of each element using the lowest ratio because empirical formula gives the simplest-whole number ration of each element

e.g. the empirical formula of benzeneC6H6 in CH

Explanation:

I HOPE IT WILL HELP YOU

4 0
2 years ago
A 50.0 −mL sample of 1.50×10−2 M Na2SO4(aq) is added to 50.0 mL of 1.28×10−2 M Ca(NO3)2(aq). What percentage of the Ca2+ remains
Norma-Jean [14]
When we have Ksp CaSO4 = 9.1x10^-6 so by substitution in Ksp formula:
Ksp CaSO4 = [Ca+2][SO4] 
1.9x10^-6   = [Ca+2][1.5x10^-2]
∴ [Ca+2] M in the solution =1.27x10^-4
when percent remaining = [Ca in solution]/[C original value] * 100
                                          = [(1.27x10^-4*(50ml+50ml)]/[1.28x10^-2*50ml]*100
                                          ≈ 2%
4 0
3 years ago
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