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Blizzard [7]
2 years ago
6

Start with Chanel’s sequence. How does a 90-degree counterclockwise rotation about the origin change the coordinates of a shape?

**SEE PIC BELOW**

Mathematics
2 answers:
zmey [24]2 years ago
8 0

When a shape is rotated, it must be rotated through a point.

  • <em>90 degrees counterclockwise rotation negates the y-coordinates, and then swap the x and y-coordinates</em>
  • <em>Chanel is incorrect</em>

The rule of 90 degrees counterclockwise is:

(x,y) \to (-y,x)

This means that:

  • <em>The y-coordinate is negated</em>
  • <em>Then the y and x coordinates are swapped</em>

<em />

However, Charlies transformation is incorrect.

  • This is so because, the shape was not rotated, but instead it was reflected  across the x-axis.
  • Then, the shape was dilated

Using points L and Q

L=(1,1)

When L is reflected across the x-axis.

The rule is:

(x, y) \to (x, -y)

So, we have:

(1, 1) \to (1, -1)

Next, it is dilated by 2.

The rule of this is:

(x,y) \to k(x,y)

So, we have:

(1,1) \to2 \times  (1,-1)

(1,1) \to (2,-2)

From the diagram, the coordinate of Q is:

Q = (2,-2)

Same as the calculated point

Hence, Chanel is incorrect

Read more about transformation at:

brainly.com/question/11709244

emmasim [6.3K]2 years ago
7 0

Answer:

So when rotating a 90 degrees counterclockwise rotation about the origin we have to change (x, y) to (-y, x).

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Answer:

Step-by-step explanation:

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\frac{5}{8}=\frac{x}{y}=\frac{x}{\frac{13}{2}-x}=\frac{2x}{13-2x}\\65-10x=16x \\26 x=65\\2x=5\\x=\frac{5}{2}\\y=\frac{13}{2}-\frac{5}{2}=\frac{8}{2}=4

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Can someone please help me
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Answer:

Lines RQ and SP are perpendicular to SR

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6 0
4 years ago
Two bonds are available on the market as follows: Bond 1: Face value $250, 5 years to maturity at a (simple) interest rate of 5%
tester [92]

The value of r is 5.95%

Step-by-step explanation:

The formula of the simple interest is I = P r t, where

  • P is the initial amount of money
  • r is the interest rate in decimal
  • t is the time

Bond 1:

∵ The face value is $250

∴ P = 250

∵ The value is in the bond for 5 years

∴ t = 5

∵ The simple interest rate is 5%

∴ r = 5% = 5 ÷ 100 = 0.05

∵ I = P r t

- Substitute the values of P, r and t in the rule

∴ I = (250)(0.05)(5) = 62.5

∴ The interest of Bond 1 is $62.5

Bond 2:

∵ The face value is $350

∴ P = 350

∵ The value is in the bond for 3 years

∴ t = 3

∵ The simple interest rate is r

∵ I = P r t

- Substitute the values of P and t in the rule

∴ I = (350)(r)(3) = 1050 r

∴ The interest of Bond 2 is 1050 r

∵ The both bonds yield the same interest to maturity

- Equate the interests of bonds 1 and 2

∵ 1050 r = 62.5

- Divide both sides by 1050

∴ r = 0.0595

- Multiply it by 100% to change it to percentage

∵ r = 0.0595 × 100% = 5.95%

∴ r = 5.95%

The value of r is 5.95%

Learn more:

You can learn more about interest in brainly.com/question/11149751

#LearnwithBrainly

3 0
3 years ago
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