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3 years ago

Based on the information in the table, which two elements are most likely in the same group, and why?

Physics

2 answers:

Gnesinka [82]3 years ago

4 0

Answer:

Explanation:

i got it right in my test

velikii [3]3 years ago

3 0

Answer: bismuth and nitrogen, because they have the same number of valence electrons

Explanation:

Elements are distributed in groups and periods in a periodic table.

Elements that belong to same groups will show similar chemical properties because they have same number of valence electrons.

The number of valence electrons in Bismuth and nitrogen are 5 and thus thus they will show similar chemical properties and thus belong to the same group.

The atomic masses of elements in a group will differ drastically.

The group number has got nothing to be the isolation year.

Thus bismuth and nitrogen belong to same group because they have the same number of valence electrons

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Dolphins and other sea creatures can leap to great heights by swimming straight up and exiting the water at a high speed. A 200

scoundrel [369]

Answer:

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Explanation:

so if a pie is baked

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3 years ago

Which element has a magnetic properties

vodomira [7]

Answer:

Since then only three elements on the periodic table have been found to be ferromagnetic at room temperature - iron (Fe), cobalt (Co), and nickel (Ni). The rare earth element gadolinium (Gd) nearly misses by only 8 degrees Celsius.

Explanation:

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3 years ago

Read 2 more answers

A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long str

mart [117]

Answer:

$7.3 ms^{-1}$

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

$Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50$

height gained by the ball is given as

$h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m$

$M$ = mass of the ball attached to string = 110 g

$V$ = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

$Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}$

Consider the collision between the two balls

$m$ = mass of the ball fired = 26 g

$v_{o}$ = initial velocity of ball fired before collision = ?

$v_{f}$ = final velocity of ball fired after collision = ?

using conservation of momentum

$m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85$

Using conservation of kinetic energy

$m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}$

3 0

3 years ago

5 Ohm 3 Ohm 2 Ohm R=?

Tema [17]

Answer:

6.2 ohm

Explanation:

Let R1 = 5 ohm

R2= 3 ohm

R3= 2 ohm

Since R3 and R2 are parallel then net resistance R' is given by

1/R' = 1/R2 + 1/R3

1/R' = 1/3 + 1/2

1/R' = 5/6

then

R' = 6/5 = 1.2 ohm

Now R1 and R' are in series, so

R = R1 + R'

R = 5 + 1.2

R = 6.2 ohm

5 0

3 years ago

A 140-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope a

RUDIKE [14]

Answer:

The constant force is 263.55 newtons

Explanation:

There's a rotational version of the Newton's second law that relates the net torque on an object with its angular acceleration by the equation:

$\tau = I\alpha$ (1)

with τ the net torque and α the angular acceleration. It’s interesting to note the similarity of that equation with the well-known equation F=ma. I that is the moment of inertia is like m in the linear case. The magnitude of a torque is defined as

$\tau = Fr\sin \theta$

with F the force applied in some point, r the distance of the point respect the axis rotation and θ the angle between the force and the radial vector that points toward the point the force is applied, in our case θ=90 and sinθ=1, then (1):

$Fr = I\alpha$ (2)

Because the applied force is constant the angular acceleration is constant too, and for constant angular acceleration we have that it's equal to the change of angular velocity over a period of time:

$\alpha=\frac{0.800}{2.00}=0.40 \frac{rev}{s^{2}}$