Question

The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 100 kPa, given that the temperature is held constant?

Answer 1

The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Effect of Pressure on Solubility

As the pressure of a gas increases, the solubility increases, and as the pressure of a gas decreases, the solubility decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

$\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }$

Where $S_{1}$ is the initial solubility

$P_{1}$ is the initial pressure

$S_{2}$ is the final solubility

$P_{2}$ is the final pressure

From the given information

$S_{1} = 0.890 \ g/L$

$P_{1} = 120 \ kPa$

$P_{2} = 100 \ kPa$

Putting the parameters into the formula, we get

$\frac{0.890}{120}=\frac{S_{2}}{100}$

$S_{2}= \frac{0.890 \times 100}{120}$

$S_{2}= 0.742 \ g/L$

Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Learn more on Solubility here: brainly.com/question/4529762