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zlopas [31]
2 years ago
7

A 1.0 L volume of gas at 27.0°C exerts a pressure of 85.5 K PA what will the pressure be at 127°C assume constant volume

Chemistry
1 answer:
Marianna [84]2 years ago
4 0

Answer:

114 kPa

Explanation:

Using Gay-Lussac's law you get the equation \frac{P1}{T1} x \frac{P2}{T2} and converting celcius you get the final equation of \frac{85.5}{27+273}  x \frac{P2}{127+273} . After dividing 85.5 by 27+273(300) you get 0.285 and then you multiply 0.285 by 127+273 (400). You finally get 114 kPa

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2 years ago
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15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams
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Answer:

\boxed {\tt A. \ d=0.85 \ g/mL}

Explanation:

Density is found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

m= 12.7 \ g\\v= 15 \ mL

Substitute the values into the formula.

d=\frac{12.7 \ g}{ 15 mL}

Divide.

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Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

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3 years ago
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Answer:

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I had to look for the problem to know the options.

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Have a nice day!

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