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zlopas [31]
2 years ago
7

A 1.0 L volume of gas at 27.0°C exerts a pressure of 85.5 K PA what will the pressure be at 127°C assume constant volume

Chemistry
1 answer:
Marianna [84]2 years ago
4 0

Answer:

114 kPa

Explanation:

Using Gay-Lussac's law you get the equation \frac{P1}{T1} x \frac{P2}{T2} and converting celcius you get the final equation of \frac{85.5}{27+273}  x \frac{P2}{127+273} . After dividing 85.5 by 27+273(300) you get 0.285 and then you multiply 0.285 by 127+273 (400). You finally get 114 kPa

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Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a te
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Answer:

n_{N_2}=6.41mol

Explanation:

¡Hola!

En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:

PV=nRT\\\\n=\frac{RT}{PV} \\\\n=\frac{0.08206\frac{atm*L}{mol*K}*(50.0+273.15)K}{740/760atm*4.25L}\\\\n=6.41mol

Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):

n_2=\frac{6.41mol*8.50L}{4.25L}\\\\n_2=12.82mol

Quiere decir que las moles de N2(g) que se agregaron son:

n_{N_2}=12.81mol-6.41mol\\\\n_{N_2}=6.41mol

¡Saludos!

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3 years ago
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