Question

Calculate the mass of sodium acetate (CHaCOONa) required to prepare 50 mL of a 0.10 M sodium acetate solution. Calculate the volume of 1 M sodium hydroxide (NaOH) needed to prepare 10 mLcf a 0.10 M sodium hydroxide solution

Answer 1

Answer:

a)mCH3COONa=?, Vsln=50mL(0.05L); [sln]=0.1M∴M≡(mol/L)

b)VslnNaOH=?; [slnNaOH]=1M; Vsln2=10mlcf; [sln2]=0.1M

Explanation:

a) PMCH3COONa=82.03g/mol

⇒ 0.05L*0,1mol/L*82.03g/mol = 0.4102g CH3COONa

R/ mCH3COONa = 0.4102g

b) V1*M1 =V2*M2......dilution form.

⇒V1*(1M) = (10mlcf)*(0.1M)

⇒V1 = ((10mlcf)*(0.1M))/(1M)

⇒V1 = 1mlcf

R/ Vsln NaOH = 1mlcf