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Ne4ueva [31]
3 years ago
9

Calculate the mass of sodium acetate (CHaCOONa) required to prepare 50 mL of a 0.10 M sodium acetate solution. Calculate the vol

ume of 1 M sodium hydroxide (NaOH) needed to prepare 10 mLcf a 0.10 M sodium hydroxide solution
Chemistry
1 answer:
Inga [223]3 years ago
3 0

Answer:

a)mCH3COONa=?, Vsln=50mL(0.05L); [sln]=0.1M∴M≡(mol/L)

b)VslnNaOH=?; [slnNaOH]=1M; Vsln2=10mlcf; [sln2]=0.1M

Explanation:

a) PMCH3COONa=82.03g/mol

⇒ 0.05L*0,1mol/L*82.03g/mol = 0.4102g CH3COONa

R/ mCH3COONa = 0.4102g

b) V1*M1 =V2*M2......dilution form.

⇒V1*(1M) = (10mlcf)*(0.1M)

⇒V1 = ((10mlcf)*(0.1M))/(1M)

⇒V1 = 1mlcf

R/ Vsln NaOH = 1mlcf

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Calculate the [OH-] given pH of 9.9
Juli2301 [7.4K]

Answer

pOH = 4.1

Explanation

<em>Given:</em>

pH = 9.9

<em>Required</em>: The concentration of OH-

Solution

pH + pOH = 14

9.9 + pOH = 14

pOH = 14-9.9

pOH = 4.1

3 0
1 year ago
25 °C = ________ K <br><br> which one <br> 298<br> 0<br> 33 <br> 197
Paraphin [41]

Answer:

298

hope this helps

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Explanation:

5 0
3 years ago
Read 2 more answers
51.7ml at 27 Celsius and 90kpa to stp
never [62]
STP is the abbreviation of standard condition for temperature and pressure which is 273.15K temperature and 1.013× 10^5 Pa pressure. Since the pressure and temperature changes, I assume the question would ask about the result of the volume. The temperature used in ideal gas should be Kelvin, so 27 Celcius would be 300.15K.
The calculation would be
PV=T
V=T/P

V2/V1= T2*P1/T1*P2
V2/V1=273.15K*  90^10^3Pa/ 300.15K *  1.013× 10^5 Pa
V2= 0.81904 * 51.7ml
V2= 42.34ml
6 0
3 years ago
The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?
Agata [3.3K]

<u>Answer:</u> The molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

PbI_2\rightleftharpoons Pb^{2+}+2I^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Pb^{2+}][I^-]^2

We are given:

K_{sp}=7.9\times 10^{-9}

Putting values in above equation, we get:

7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L

Hence, the molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

3 0
3 years ago
What is the empirical formula for the following molecular formula: C10H5O2
Tju [1.3M]

The empirical formula is the same as the molecular formula : C₁₀H₅O₂

<h3>Further explanation</h3>

Given

Molecular formula : C₁₀H₅O₂

Required

The empirical formula

Solution

The empirical formula (EF) is the smallest comparison of atoms of compound forming elements.  

The molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

<em>(EF)n=MF </em>

(EF)n = C₁₀H₅O₂

If we divide by the number of moles of Oxygen (the smallest) which is 2 then the moles of Hydrogen will be a decimal number (not whole), which is 2.5, then the empirical formula is the same as the molecular formula

4 0
3 years ago
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