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3 years ago

Which of the following best describes chicken noodle soup?

Chemistry

2 answers:

Anna71 [15]3 years ago

8 0

Mixture, because of the warm water, the heat from the stove or microwave, and the food itself.

OlgaM077 [116]3 years ago

4 0

B. Mixture, because the noodles, chicken, and chicken broth are mixed together.

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A _______ pattern organizes a speech by incorporating repetition and variations of themes and ideas

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Answer:

A wave pattern organizes a speech

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3 years ago

In the Chemical formula H 2o which description explains what the two represents

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Answer:

The number of hydrogen atoms

Explanation:

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3 years ago

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Any 4 characteristics of catalyst

Ivan

Answer:

Any 4 characteristic of catalyst are:

1. Catalysts remain unchanged at the end of chemical reaction in their mass and structure.

2. They donot start the chemical reaction.

3. They change the rate of the chemical reaction.

4. Catalyst is specific to the chemical reaction. It means that one catalyst can alter the rate of only one chemical reaction.

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3 years ago

Suppose two gases in a container have a total pressure of 1.30 atm. What is the pressure of gas B if the partial pressure of gas

Korolek [52]

Answer:

P(B) = 0.45 atm

Explanation:

Given data:

Total pressure = 1.30 atm

Partial pressure of A = 0.85 atm

Pressure of B = ?

Solution:

Total pressure = P(A) + P(B)

P(B) = Total pressure - P(A)

P(B) = 1.30 atm - 0.85 atm

P(B) = 0.45 atm

5 0

3 years ago

The specific reaction rate of a reaction at 492k is 2.46 second inverse and at 528k 47.5 second inverse.find activation energy a

crimeas [40]

Answer:

Ea = 177x10³ J/mol

ko = $1.52x10^{19}$ J/mol

Explanation:

The specific reaction rate can be calculated by Arrhenius equation:

$k = koxe^{-Ea/RT}$

Where k0 is a constant, Ea is the activation energy, R is the gas constant, and T the temperature in Kelvin.

k depends on the temperature, so, we can divide the k of two different temperatures:

$\frac{k1}{k2} = \frac{koxe^{-Ea/RT1}}{koxe^{-Ea/RT2}}$

$\frac{k1}{k2} = e^{-Ea/RT1 + Ea/RT2}$

Applying natural logathim in both sides of the equations:

ln(k1/k2) = Ea/RT2 - Ea/RT1

ln(k1/k2) = (Ea/R)x(1/T2 - 1/T1)

R = 8.314 J/mol.K

ln(2.46/47.5) = (Ea/8.314)x(1/528 - 1/492)

ln(0.052) = (Ea/8.314)x(-1.38x $10^{-4}$

-1.67x $10^{-5}$ xEa = -2.95

Ea = 177x10³ J/mol

To find ko, we just need to substitute Ea in one of the specific reaction rate equation:

$k1 = koxe^{-Ea/RT1}$

$2.46 = koxe^{-177x10^3/8.314x492}$

$1.61x10^{-19}ko = 2.46$

ko = $1.52x10^{19}$ J/mol

3 0

3 years ago