What is Cesium abbreviated

Afina-wow [57]

Answer:

Covalent

Explanation:

A molecule of C₂H₅OH has C-C, C-H, C-O, and O-H bonds.

A bond between A and B will be ionic if the difference between their electronegativities (ΔEN) is greater than 1.6.

$\begin{array}{ccc}\textbf{Bond} & \textbf{$\Delta$EN} & \textbf{Polarity}\\\text{C-C} & 2.55 - 2.55 = 0.00 & \text{Nonpolar covalent}\\\text{C-H} & 2.55 - 2.20 = 0.35 & \text{Nonpolar covalent}\\\text{C-O} & 3.44 - 2.55 = 0.89 & \text{Polar covalent}\\\text{O-H} & 3.44 - 2.20 = 1.24 & \text{Polar covalent}\\\end{array}$

No bond has a large enough ΔEN to be ionic.

C₂H₅OH is a covalent molecule.

6 0

3 years ago

During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. S

Kay [80]

<u>Answer:</u> The below calculations proves that the rate of diffusion of $^{235}UF_6$ is 0.4 % faster than the rate of diffusion of $^{238}UF_6$

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of $^{235}UF_6=349.034348g/mol$

Molar mass of $^{238}UF_6=352.041206g/mol$

By taking their ratio, we get:

$\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{M_{(^{238}UF_6)}}{M_{(^{235}UF_6)}}}$

$\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{352.041206}{349.034348}}\\\\\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\frac{1.00429816}{1}$

From the above relation, it is clear that rate of effusion of $^{235}UF_6$ is faster than $^{238}UF_6$

Difference in the rate of both the gases, $Rate_{(^{235}UF_6)}-Rate_{(^{238}UF_6)}=1.00429816-1=0.00429816$

To calculate the percentage increase in the rate, we use the equation:

$\%\text{ increase}=\frac{\Delta R}{Rate_{(^{235}UF_6)}}\times 100$

Putting values in above equation, we get:

$\%\text{ increase}=\frac{0.00429816}{1.00429816}\times 100\\\\\%\text{ increase}=0.4\%$

The above calculations proves that the rate of diffusion of $^{235}UF_6$ is 0.4 % faster than the rate of diffusion of $^{238}UF_6$

3 0

3 years ago

The diameter of a circular swimming pool is 12 feet. Find circumference Round to the nearest tenth . Use 3.14 for pi

-BARSIC- [3]

Answer:

the pool's circumference is 37.7 ft^2 (rounded to nearest tenth).

6 0

3 years ago

The sum of two integers is -4. Can the two integers both be positive?

kaheart [24]

Answer: No.

Explanation: A negative integer can only be made with 2 negative integers or 1 positive and 1 negative integer.

3 0

3 years ago

Find the mass in grams of 2.00x10^23 molecules of F2

earnstyle [38]

Hello!

To find the mass in grams of 2.00 * 10²³ molecules of F₂ you'll need to apply the Avogadro's number, which tells the number of molecules in a mol of a substance, and the Molar Mass, which tells the weight of a mole of a substance. These two quantities are used in the following conversion factor:

$2,00*10^{23} moleculesF_2* \frac{1 mol F_2}{6,02*10^{23} moleculesF_2 }* \frac{37,997 g F_2}{1 mol F_2} \\ \\ =12,51 g F_2$

So, the mass of 2.00 * 10²³ molecules of F₂ is 12,51 g

Have a nice day!

4 0

3 years ago