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Ann [662]
3 years ago
8

A chemical reaction needs to occur at a certain temperature, but one liquid is coming from a reactor at a much hotter temperatur

e. what might be used to cool the liquid? question 3 options: cooling pool steam turbine heat exchanger boiler
Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
7 0

The medium that might be used to cool the hot liquid coming from a reactor is : ( C ) Heat exchanger

<h3>Function of the heat exchanger</h3>

Heat exchanger is used  for the transfer of heat between liquids to be used in a chemical reaction, It can be used for both Cooling and heating to achieve the desired temperature.

The liquid coming from a reactor which posses a very high temperature will be passed through the heat exchanger so that its temperature will attain the required temperature for the experiment.

Hence we can conclude that The medium that might be used to cool the hot liquid coming from a reactor is Heat exchanger.

Learn more about heat exchanger : brainly.com/question/25154137

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When you boil water on the stove some steam will rise from the pan. Which of these is a true statement right as the water begins
Kay [80]

B. The water and steam contain the same amount of energy.

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What is the difference between a molecular formula and a molecular modle?
ankoles [38]
The molecular formula tell us what elements the atoms are, and how many moles and atoms are attributed toward each element.
The molecular model tells us how the atoms/elements are bonded together.

Molecular formula : CH4

                                  H
                                   l
Molecular model:   H -- C -- H
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3 0
3 years ago
What is the mass of a cube measuring 3cm on each side that had a density of 8.1g/cm3?
Hunter-Best [27]

Answer:

48.6 g

Explanation:

Given data:

Length of one side = 3 cm

Density of cube = 8.1 g/cm³

Mass of cube = ?

Solution:

First of all we will calculate the volume of cube.

V = length × height × width

V = 3 cm × 3cm× 3cm

V = 27cm³

Now we will determine the mass by using density formula.

d = m/v

d = density

m = mass

v = volume

8.1 g/cm³ = m/ 27 cm³

m = 8.1 g/cm³ ×27 cm³

m = 48.6 g

6 0
3 years ago
A particular 3.0 L solution contains 2.5 mmol (millimoles) of a substance. What is the concentration of this solution in number
bearhunter [10]

Answer: 0.83mol/m3

Explanation:

Number of mole = 2.5 mmol = 0.0025mol

Recall

1L = 0.001m3

Therefore 3L = 3x0.001 = 0.003m3

0.003m3 contains 0.0025mol

Therefore, 1m3 will contain = 0.0025/0.003 = 0.83mol

The concentration in mol/m3 is 0.83mol/m3

8 0
4 years ago
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